3 years ago

How do u solve the equation using the quadratic formula

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

7 0

Answer:

you could use the formula

Step-by-step explanation:

That is x = -b+√b^2 - 4ac/2a

where ur x is

x= -b+√b^2-4ac/2a or

x= -b-√b^2-4ac/2a

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3 years ago

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3(4x^2y^3 + 2x^3) – 4(9x^3y^2 – 6x^2y^3) How to solve pls?

babunello [35]

Answer:

$3(4 {x}^{2} {y}^{3} + 2 {x}^{3}) - 4(9 {x}^{3} {y}^{2} - 6 {x}^{2} {y}^{3} ) \\ = (12 {x}^{2} {y}^{3} + 6 {x}^{3} ) - (36{x}^{3} {y}^{2} - 24{x}^{2} {y}^{3}) \\ = (12 {x}^{2} {y}^{3} + 6 {x}^{3} ) + ( - 36{x}^{3} {y}^{2} + 24{x}^{2} {y}^{3}) \\ = - 36{x}^{3} {y}^{2} + 36x^{2} {y}^{3} + 6 {x}^{3}$

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2 years ago

Compare the following fraction 4/3 and 5/2 -3/2. -4/5

zavuch27 [327]

Answer:

Step-by-step explanation:

to compare them, we need to convert them into like fractions

4/3 and 5/2

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15/6 is greater than 8/6

so 5/2 is greater than 4/3

similarly,

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we need to convert them into like fractions

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2 years ago