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Aliun [14]
3 years ago
11

2k-3(4-k)=3k+4 what is the value for x

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

k=8

Step-by-step explanation:

2k-12+3k=3k+4

5k-12=3k+4

2x-12=4

2k=16

k=8

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Rotate triangle P 90° clockwise about the point (2, -1).<br>​
dlinn [17]

Answer:

Step-by-step explanation:

If we are rotating about the point (2,-1) , then we first need to translate the triangle two points to the left so that point P is at location (2,-1). Once we have that we rotate everything 90 degrees clockwise, while maintaining the same distance and angles between each point in the triangle. After doing this we will get the triangle seen in the attached picture below. Which is fully rotated 90 degrees clockwise about the point (2,-1)

3 0
3 years ago
What number produces a rational number when added to 0.25?
MrRissso [65]

Answer:

.625 to get .875

Step-by-step explanation:

what is a rational number

8 0
3 years ago
Read 2 more answers
Which of the following represents the set of possible rational roots for the
kakasveta [241]

Answer:

<h2>The rational root of the given polynomial is 42.59.</h2>

Step-by-step explanation:

The polynomial is given by 2x + 5.82 - 81 - 10 = 0

or, 2x + 5.82 - 91 = 0

or, 2x = 85.18

or, x = 42.59.

The rational roots of any polynomial = the ratio of the factors of constants and factors of leading coefficients.

7 0
3 years ago
The time, t in seconds that it takes a car to travel a quarter-mile when starting from a full stop can be estimated by using the
sammy [17]

The computation of the power shows that Natasha was right as the value gotten is 295hp.

<h3>How to calculate power?</h3>

From the information given, t is given as 5.825 to the cube root of w/p.

In this case, the value of p will be:

p = w/t³(5.823)³

p = 3590(5.823)³ / (13.4)³

p = 708828.13/2406.104

p = 295hp

In conclusion, Natasha was correct.

Learn more about power on:

brainly.com/question/24858512

5 0
2 years ago
1. Find the vertices and locate the foci for the hyperbola whose equation is given.
Irina18 [472]
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\bf \textit{now, for the foci, the foci are "c" distance from the center point}\\\\\&#10;whereas\qquad c=\sqrt{a^2+b^2}\qquad \textit{ that is }\qquad  h\pm \sqrt{a^2+b^2}

notice your "a" and "b" components, to get the distance "c" from the center to either foci and the vertices, of course, are h + a, k and h - a, k
5 0
3 years ago
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