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wel
3 years ago
13

How many complex roots does 5x^6 + x^4 3 = 0 have?

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0
Thank you for posting your question here at brainly. Feel free to ask more questions.  

The best and most correct answer among the choices provided by the question is <span>4</span>.<span>       
    </span><span>
Hope my answer would be a great help for you.</span>
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Which of the following numbers can be exposed as repeated decimals? 5/7 4/5 7/9 5/8
rodikova [14]

Answer:

C.

Step-by-step explanation:

5/7=.714285714 and so on

7/9=.777777778 and so on

5 0
3 years ago
Explain how you can find the sign of the product of two or more rational numbers.
makkiz [27]
Rational and product
6 0
3 years ago
when finding the distance between two rational numbers on a number line, does the order of the numbers you subtract matter?
sergeinik [125]

Answer:

the distance between two numbers and on the number line is . Note that the distance between two numbers is always positive, no matter the order. But the difference can be positive or negative, depending on the order.

Step-by-step explanation:

the distance between two points on a line is abs(x1-x2) which is a symmetric function abs(y)=abs(-y) so abs(x1-x2)=abs(-(x1-x2))=abs(x2-x1) so the order does not matter since you take abs after the subtraction.

hopes this helps

and mark me brainliest if it does

Have a good day!

7 0
3 years ago
A man is in a boat 2 miles from the nearest point on the coast. He is to go to point Q, located 3 miles down the coast and 1 mil
mafiozo [28]

Answer:

The answer is "0.45385".

Step-by-step explanation:

The time is taken to reach the coast = \frac{\sqrt{(2^2 + x^2)}}{4}

The  time is taken to reach Q after reaching the coast = \frac{\sqrt{(1 + (3-x)^2)}}{4}

Total time, T= \frac{\sqrt{(1 + (3-x)^2)}}{4}+  \frac{\sqrt{(1 + (3-x)^2)}}{4}

This has to be minimum,

\to \frac{dt}{dx} = 0

\to \frac{\sqrt{(2^2 + x^2)}}{2} + \frac{\sqrt{1 + (3-x)^2}}{3}\\\\ \frac{x}{4}\sqrt{(4+x^2)} + \frac{(x-3)}{(4\sqrt{(x^2-6x+10)}} = 0\\\\\frac{x^2}{16} \times (4+x^2) = \frac{(x-3)^2}{16  \times (x^2-6x+10)}\\\\x^2(4+x^2) = \frac{(x-3)^2}{(x^2-6x+10)}\\\\4x^2+x^4 = \frac{ x^2+9-6x}{(x^2-6x+10)}\\\\ 4x^2+x^4(x^2-6x+10) = x^2+9-6x\\\\4x^4-24x^3+40x^2+x^6-6x^5+10x^4= x^2+9-6x\\\\x^6-6x^5+ 14x^4-24x^3+39x^2+6x-9=0\\\\

x=0.45385

6 0
3 years ago
Please help me, it's urgent
Monica [59]

Answer:

y = 4x +5

Slope is 4

Intercept is 5

Step-by-step explanation:

Using, y1= 1 and x1= -1

And, y2 = 13, x2 = 2

\frac{y2 - y1}{x2 - x1}  =  \frac{y - y1}{x - x1}

\frac{13 - 1}{2 - ( - 1)}  =  \frac{y - 1}{x - ( - 1)}

\frac{12}{3}  =  \frac{y - 1}{x  + 1}

4 =  \frac{y - 1}{x + 1}

y - 1 = 4(x + 1)

y-1 = 4x +4

y = 4x +4 +1 = 4x +5

4 0
3 years ago
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