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Oxana [17]
3 years ago
9

PLZ HELP

Mathematics
2 answers:
amid [387]3 years ago
6 0
Plug in the points.

3(a-4b) a=-2 b=5

3(-2-4*5)

Work in the parenthesis first. (-2-20)

-22

-22*3= -66

I think you wrote your answer choices wrong because I checked my answer. I made sure to use PEMDAS as well.

I hope this helps!
~cupcake
Blizzard [7]3 years ago
6 0
All you do is insert -2 for a and 5 for b. So it becomes: 3(-2-4[5]). First you solve inside the parentheses because of pemdas (parentheses, exponents, multiplication/division, and addition/subtraction). The next step is multiplication, so you multiply -4 by 5 and end up with -20. So the problem is now 3(-2-20). Next you subtract -2 by 20 and get -22. Finally all you have left is 3(-22) Multiply that and get -66.

I'm sorry none of the answers worked but I triple checked my work. Many there's a typo?
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Step-by-step explanation:

So, 5 walls = 4500 ft2 & since there are 5 people (all doing equal work) then each man paints 900 ft2 in 20 minutes. So, the total time is 20 minutes.

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4 years ago
If f(x) = (1/8)(8^x), what is f(3)?
Salsk061 [2.6K]

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6 0
3 years ago
Read 2 more answers
Which of the following is the value of the expression 2x^2+1 when x = -2?
azamat

Answer: 9


Step-by-step explanation:

1.) you first want to plug in your x= -2


2.) 2*-2^2=1


3.) Solve in order.


4.) 2*-2 = -4


5.) -4 * -2 (your power) = 8 , it is a negative two because x = -2 and where it lands in the order of operations that is how you solve.


6.) 8 + 1 = 9


7.) =9 .


8 0
3 years ago
Read 2 more answers
Which of the points is a solution to the following system of equations? -5x- 3/2y=15 3x+5/6 y=-44/3
tatiyna

<em>Note: Your question sounds a little unclear, but I am assuming that your system of equations is:</em>

-5x-\:\frac{3}{2}y=15

3x+\frac{5}{6}y=-\frac{44}{3}

  • It would anyways clear your concept because the procedure to find the solutions remains the same for any set of a system of equations.

Answer:

The solution of the system of equations be:

x=-\frac{57}{2},\:y=85

Step-by-step explanation:

Given the system of equations

-5x-\:\frac{3}{2}y=15

3x+\frac{5}{6}y=-\frac{44}{3}

solving the system of equations

\begin{bmatrix}-5x-\frac{3}{2}y=15\\ 3x+\frac{5}{6}y=-\frac{44}{3}\end{bmatrix}

\mathrm{Multiply\:}-5x-\frac{3}{2}y=15\mathrm{\:by\:}3\:\mathrm{:}\:\quad \:-15x-\frac{9}{2}y=45

\mathrm{Multiply\:}3x+\frac{5}{6}y=-\frac{44}{3}\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:15x+\frac{25}{6}y=-\frac{220}{3}

so the system of equations becomes

\begin{bmatrix}-15x-\frac{9}{2}y=45\\ 15x+\frac{25}{6}y=-\frac{220}{3}\end{bmatrix}

adding the equations

15x+\frac{25}{6}y=-\frac{220}{3}

+

\underline{-15x-\frac{9}{2}y=45}

-\frac{1}{3}y=-\frac{85}{3}

so

\begin{bmatrix}-15x-\frac{9}{2}y=45\\ -\frac{1}{3}y=-\frac{85}{3}\end{bmatrix}

solving -\frac{1}{3}y=-\frac{85}{3} for y

-\frac{1}{3}y=-\frac{85}{3}

Multiply both sides by -3

\left(-\frac{1}{3}y\right)\left(-3\right)=\left(-\frac{85}{3}\right)\left(-3\right)

y=85

\mathrm{For\:}-15x-\frac{9}{2}y=45\mathrm{\:plug\:in\:}y=85

-15x-\frac{9}{2}\cdot \:85=45

\mathrm{Add\:}\frac{765}{2}\mathrm{\:to\:both\:sides}

-15x-\frac{765}{2}+\frac{765}{2}=45+\frac{765}{2}

-15x=\frac{855}{2}

\mathrm{Divide\:both\:sides\:by\:}-15

\frac{-15x}{-15}=\frac{\frac{855}{2}}{-15}

x=-\frac{57}{2}

Therefore, the solution of the system of equations be:

x=-\frac{57}{2},\:y=85

7 0
3 years ago
Question 1
Bad White [126]

Answer:

n = -15 and n = 9. n = -15 is not reasonable because you can't have negative boxes or negative units of measurement.

Step-by-step explanation:

8(n + 2)(n + 4) = 1,144

(n + 2)(n + 4) = 143

n^2 + 2n + 4n + 8 = 143

n^2 + 6n - 135 = 0

(n + 15)(n - 9) = 0

n + 15 = 0

n = -15

n - 9 = 0

n = 9

I got two solutions: n = -15 and n = 9. Only one is reasonable because you cannot have a negative number of boxes or negative weight.

Hope this helps!

6 0
4 years ago
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