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3 years ago

PLZ HELP

2 answers:

6 0

Plug in the points.

3(a-4b) a=-2 b=5

3(-2-4*5)

Work in the parenthesis first. (-2-20)

-22

-22*3= -66

I think you wrote your answer choices wrong because I checked my answer. I made sure to use PEMDAS as well.

I hope this helps!
~cupcake

Blizzard [7]3 years ago

6 0

All you do is insert -2 for a and 5 for b. So it becomes: 3(-2-4[5]). First you solve inside the parentheses because of pemdas (parentheses, exponents, multiplication/division, and addition/subtraction). The next step is multiplication, so you multiply -4 by 5 and end up with -20. So the problem is now 3(-2-20). Next you subtract -2 by 20 and get -22. Finally all you have left is 3(-22) Multiply that and get -66.

I'm sorry none of the answers worked but I triple checked my work. Many there's a typo?

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Step-by-step explanation:

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If f(x) = (1/8)(8^x), what is f(3)?

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3 years ago

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Which of the following is the value of the expression 2x^2+1 when x = -2?

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Step-by-step explanation:

1.) you first want to plug in your x= -2

2.) 2*-2^2=1

3.) Solve in order.

4.) 2*-2 = -4

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8 0

3 years ago

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Which of the points is a solution to the following system of equations? -5x- 3/2y=15 3x+5/6 y=-44/3

tatiyna

<em>Note: Your question sounds a little unclear, but I am assuming that your system of equations is:</em>

$-5x-\:\frac{3}{2}y=15$

$3x+\frac{5}{6}y=-\frac{44}{3}$

It would anyways clear your concept because the procedure to find the solutions remains the same for any set of a system of equations.

Answer:

The solution of the system of equations be:

$x=-\frac{57}{2},\:y=85$

Step-by-step explanation:

Given the system of equations

$-5x-\:\frac{3}{2}y=15$

$3x+\frac{5}{6}y=-\frac{44}{3}$

solving the system of equations

$\begin{bmatrix}-5x-\frac{3}{2}y=15\\ 3x+\frac{5}{6}y=-\frac{44}{3}\end{bmatrix}$

$\mathrm{Multiply\:}-5x-\frac{3}{2}y=15\mathrm{\:by\:}3\:\mathrm{:}\:\quad \:-15x-\frac{9}{2}y=45$

$\mathrm{Multiply\:}3x+\frac{5}{6}y=-\frac{44}{3}\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:15x+\frac{25}{6}y=-\frac{220}{3}$

so the system of equations becomes

$\begin{bmatrix}-15x-\frac{9}{2}y=45\\ 15x+\frac{25}{6}y=-\frac{220}{3}\end{bmatrix}$

adding the equations

$15x+\frac{25}{6}y=-\frac{220}{3}$

$+$

$\underline{-15x-\frac{9}{2}y=45}$

$-\frac{1}{3}y=-\frac{85}{3}$

$\begin{bmatrix}-15x-\frac{9}{2}y=45\\ -\frac{1}{3}y=-\frac{85}{3}\end{bmatrix}$

solving $-\frac{1}{3}y=-\frac{85}{3}$ for y

$-\frac{1}{3}y=-\frac{85}{3}$

Multiply both sides by -3

$\left(-\frac{1}{3}y\right)\left(-3\right)=\left(-\frac{85}{3}\right)\left(-3\right)$

$y=85$

$\mathrm{For\:}-15x-\frac{9}{2}y=45\mathrm{\:plug\:in\:}y=85$

$-15x-\frac{9}{2}\cdot \:85=45$

$\mathrm{Add\:}\frac{765}{2}\mathrm{\:to\:both\:sides}$

$-15x-\frac{765}{2}+\frac{765}{2}=45+\frac{765}{2}$

$-15x=\frac{855}{2}$

$\mathrm{Divide\:both\:sides\:by\:}-15$

$\frac{-15x}{-15}=\frac{\frac{855}{2}}{-15}$

$x=-\frac{57}{2}$

Therefore, the solution of the system of equations be:

$x=-\frac{57}{2},\:y=85$

7 0

3 years ago

Question 1

Bad White [126]

Answer:

n = -15 and n = 9. n = -15 is not reasonable because you can't have negative boxes or negative units of measurement.

Step-by-step explanation:

8(n + 2)(n + 4) = 1,144

(n + 2)(n + 4) = 143

n^2 + 2n + 4n + 8 = 143

n^2 + 6n - 135 = 0

(n + 15)(n - 9) = 0

n + 15 = 0

n = -15

n - 9 = 0

n = 9

I got two solutions: n = -15 and n = 9. Only one is reasonable because you cannot have a negative number of boxes or negative weight.

Hope this helps!

6 0

4 years ago