To find the total probability, we first need to solve for the probability of the individual events.
Event 1:
P(consonant)=7/11
We know this to be true because out of the 11 total possibilities for the event, 7 of them are consonants.
R E P L A C E M E N T
Event 2
P(e)=3/10
We know this to be true because out of the 10 total possibilities for the event (since we didn't replace the first card we withdrew), 3 of them are the letter 'e'.
R E P L A C E M E N T (-1 to account for the first card we withdrew)
The possibility of both events...
P(consonant then 'e')=7/11*3/10=21/110
Answer: P=21/110
2(3w-2+w)
=2(4w-2)
=8w-4
the formula for solving perimeters is 2(WL). so L=3w-2, because the question said the length is 2 units shorter than 3 times the width, and the width is w. so the final equation is <span>2(3w-2+w), and then you just have to simplify that </span>
Answer:
awnser G
Step-by-step explanation:
= 0.41667
= 0.375
You are correct! 0.41667>0.375
Numbers that can be greater than .05 and less than .06 is .051 through .059 due to its place value.
