Greatest common factor (or denominator) is 6,
least common multiple is 180
hmm
(note:
I spent like 30 mins trying to use a math only of finding the values
but it didn't work so I did a force brute and elimination method
explained below)
so
a and b must be multiples of 6
so list all the multiples of 6
wait
180=6*30
and 30's factors are 1,2,3,5,6,10,15,30 so only list the numbers that
are the result of multiplying 6 and any of those numbers in that list
(so we can have the lcm of 180)
so
6*1=6
6*2=12
6*3=18
6*5=30
6*6=36
6*10=60
6*15=90
6*30=180
these are our possible candidates for the 2 numbers
now we must find the pair that has a GCD of only 6
doing the math is long and tedious so do it yourself (trial and error)
we see that our choices that fulfill both requirements (GCD of 6 and LCM of 180) are
90&12
60&18
30&36
sum them to find the least one
90+12=102
60+18=78
30+36=66
the least possible sum is 66
Hans would take 13.5 seconds to run 50 meters
Priya would take 12 seconds to run 50 meters
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Since they each ran 10 meters for a certain amount of time you would multiply the seconds by 5 since 10x5=50
When you do that you get
13.5 for Han's time by multiplying 2.7x5=13.5
and
12 seconds for Priya's time by multiplying 2.4x5
1/2 ÷10=1/20 because you multiply the bottoms
3÷1/6= 18 because it is the same as 3×6
Answer:
should be added to the given equation.
Step-by-step explanation:
Let a is added to the given equation.
According to the given condition,
So, should be added to the given equation.
Answer:
your answer should be (-3,-7)
