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DedPeter [7]
3 years ago
12

How to simplify -1(2ab^3)^5?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0
I think this is it .

kozerog [31]3 years ago
4 0

- 1(2ab {}^{3} )^{5}  \\  \\  \\  \\   =  >  - 1 \times  {(2ab {}^{3} )}^{5}  \\  \\  \\  =  >  - 1 \times  {(2)}^{5}  \times  {(a)}^{5}  \times ( {(b)}^{3}  ){}^{5}  \\  \\  \\  =  >  - 1 \times 32 \times  {a}^{5}  \times  {b}^{3 \times 5}  \\  \\  \\  =  >  - 1 \times 32 \times  {a}^{5}  \times  {b}^{15}  \\  \\  \\  =  >  - 32 {a}^{5}  {b}^{15}
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maks197457 [2]

Answer:

0.11659...cm3

Step-by-step explanation:

To find volume you would have to plug it in the formula Volume= Mass / density so if we plug it in it will be, X(volume): 26(mass)/223(density) you will get 0.11659...cm3

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draw a large triangle with three acute angles. construct the angle bisector of all three angles of triangle.
IceJOKER [234]

Answer:

The angle bisector is  construct.

Step-by-step explanation:

We used the geogebra.org site. We first constructed a large triangle with acute angles. Then from point A we made a semicircular section to its sides. At the intersection of the sides and the semicircular section, we construct two circles so that they intersect. Then from the point A we draw a  line through the intersection of the circles and thus we obtain the bisector of the angle.

We repeat the same procedure for point B and for point C. In this way, we obtain a bisector for all angles of a triangle.

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3 years ago
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mariarad [96]
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3 years ago
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Simplify x + 8x - 3x
malfutka [58]

Answer:

6x

Step-by-step explanation:

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5 0
3 years ago
Rectangle ABCD is reflected over the y-axis. What rule shows the input and output of the reflection, and what is the new coordin
scZoUnD [109]

Answer:

As given Rectangle ABCD is reflected over the y- axis.

When a shape or geometrical figure is reflected through a line it's distance that is distance of image from line and distance of Pre-image from that line is always same.Also perpendicular distance of vertices of any polygon that is considered for reflection has same distance from that line after reflection and before reflection.

Suppose the coordinate of A be (x,y) and considering Rectangle A B CD lie in first quadrant then when it is reflected through y - axis that is through the line x=0, it's new coordinate will become A' (-x,y).

If rectangle is in second quadrant having Vertices that is vertices of A (-x,y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,y).

If rectangle is in third quadrant having Vertices that is vertices of A (-x,-y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,-y).

If rectangle is in fourth quadrant having Vertices that is vertices of A (x,-y) then reflected over line that is x=0,→y axis then Vertices of A' (-x,-y).

5 0
3 years ago
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