Answer: In the big cat phylogeny, the leopard is not more closely related to the tiger than to snow leopard. This is the false statement. Rest are true as the leopard is more closely related to the jaguar than to the snow leopard.
This is a typical example of R selection life strategy. These species, including the Atlantic cod, produce a large number of offspring with a low chance of surviving to adulthood. This strategy is particularly successful in environments that are unstable. The main advantage of this strategy in changing environments is that the ''cost'' of making offspring is very low, so you the species can produce large numbers offspring, ensuring that at least some of them will survive into adulthood and continue the species.
Natural selection, in this case, favors the individuals that are able to adapt the fastest to the changing conditions.
Gases have no defined shape or volume.
Water diffuses from the lumen into the interstitial space during the reabsorption of water in the proximal convoluted tubule due to an increase in the interstitium's osmolarity.
Reabsorption is the process by which water and solutes from the PCT are injected into the blood. From the proximal convoluted tubule, the solutes and water go to the interstitium before entering the peritubular capillaries. The majority of the solutes and 99 percent of the water filtered by the nephron must be reabsorbed; all of these chemicals were "absorbed" in the digestive tract. The peritubular and vasa recta capillaries return reabsorbed fluids and chemicals to the circulation.
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Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
