-5-(15y-1)=2(7y-16)-y
1 answer:
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E
Given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
The x-coordinate of the vertex is
= -
y = 10x² + 5x - 7 is in standard form
with a = 10, b = 5 and c = - 7, hence
= -
= -
Substitute this value into the equation for y-coordinate
y = 10 (- )² + 5 (-
) - 7
= -
- 7
= -
-
= -
vertex = (- 0.25, - 7.625 ) → E