Question

(2

Answer 1

Answer:

The equation is,

$(x+1)^{2} \times (x+2) = 0$

Step-by-step explanation:

According to the question, the equation is cubic and have roots -1 (with multiplicity of 2) and -2.

So, the equation is,

$(x+1)^{2} \times (x+2) = 0$

[Since, when a , b , c are the roots of a cubic equation, the equation is

given by $(x-a) \times (x-b) \times (x-c) = 0$ ]