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grin007 [14]
3 years ago
7

The graph shows the quadratic function f(x) . What is the average rate of change for the quadratic function from x = 6 to x = 8?

Enter your answer in the box.

Mathematics
2 answers:
vodomira [7]3 years ago
7 0
The rate of change is -1
taurus [48]3 years ago
7 0

Answer:

The average rate of change for the quadratic function from x = 6 to x = 8 is -1.

Step-by-step explanation:

The average rate of change for the quadratic function from x₁ to x₂ is defined as

m=\frac{f(x_2)-f(x_1)}{x_2-x_1}

From the given graph it is clear that the value of function is 6 at x=6 and the value of function is 4 at x=8.

The average rate of change for the quadratic function from x = 6 to x = 8.

m=\frac{f(8)-f(6)}{8-6}

m=\frac{4-6}{2}

m=\frac{-2}{2}

m=-1

Therefore the average rate of change for the quadratic function from x = 6 to x = 8 is -1.

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Describe and correct any error a student may have made when solving the equation
Lady_Fox [76]

Answer:

The student made an error during the distributive property in the second step where they multiplied 0.15 by -0.2 to equal -0.3 when it should have been -0.03.

Step-by-step explanation:

0.15(y-0.2)=2-0.5(1-y)\\0.15y-0.03=2-0.5+0.5y\\0.15y-0.03=1.5+0.5y\\100(0.15y-0.03)=100(1.5+0.5y)\\15y-3=150+50y\\15y-3-15y-150=150+50y-15y-150\\-153=35y\\-\frac{153}{35}=y

6 0
2 years ago
Evangeline is making snack bags for her class. If she can fill 5/8 of her snack bags with 1 2/3 cups of pretzels, how many cups
brilliants [131]

Answer:

2 2/3

Step-by-step explanation:

For each of her snack bag, she can fill it with a 1/3 cup of pretzels

1/3 x 8 = 2 2/3 cups

4 0
2 years ago
A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
T divided by -4 equals nine
SpyIntel [72]

Answer:

54

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A) Solve 3(x - 5) = 18
Anna [14]

3x_15=18

3x=18+15

3x=33

x=11

8 0
3 years ago
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