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V125BC [204]
3 years ago
9

Ella completed the division problem below What is Ellen’s error? She included a 0 in the quotient, which does not belong. She mu

ltiplied the dividend by 100 instead of 10. She should have multiplied both numbers by 100. She did not subtract correctly in one of the steps.
Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

She multiplied the dividend by 100 instead of 10.

Step-by-step explanation:

Ella multiplied the divisor by 10 but mistakenly she multiplied the dividend by 100 instead of 10.

So her division problem changed totally.

Therefore, the correct answer option is B. She multiplied the dividend by 100 instead of 10.

dimaraw [331]3 years ago
5 0

Answer:

the correct answer option is B. She multiplied the dividend by 100 instead of 10.

Step-by-step explanation:

Ella multiplied the divisor by 10 but mistakenly she multiplied the dividend by 100 instead of 10.

So her division problem changed totally.

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Find the surface area of the right rectangular prisim
Vlad [161]

Answer:

46 units^2

Step-by-step explanation:

The formula for surface area of a rectangular prism is

SA = 2(lw +lh+wh)  where l is length, w is width and h is height

SA = 2 (2.5* 4+ 2.5*2 + 4*2)

      = 2 (10+5+8)

       = 2( 23)

       = 46 units^2

4 0
3 years ago
Reduce this algebraic fraction 27c^4d^5/9c^7d^4 ...?
Naddika [18.5K]
The answer is \frac{3d}{ c^{3}}

The fraction is: \frac{27 c^{4} d^{5}}{9 c^{7}  d^{4} }
Let's rewrite it: \frac{27 c^{4} d^{5}}{9 c^{7} d^{4} }= \frac{27}{9}*\frac{c^{4}}{c^{7}}*\frac{d^{5}}{d^{4} }

Now, let's use the rule \frac{ x^{a} }{ x^{b}} =  x^{a-b} = \frac{1}{ x^{b-a} }:
\frac{27}{9}*\frac{c^{4}}{c^{7}}*\frac{d^{5}}{d^{4} }=3* \frac{1}{c^{7-4}}  * d^{5-4} =3* \frac{1}{ c^{3} } *d^{1}= \frac{3d}{ c^{3} }
5 0
3 years ago
If X = 2 centimeters, Y = 6 centimeters, and Z = 6 centimeters, what is the area of the object?
Sedbober [7]

In order to answer the question, it's absolutely essential to have
enough of a description of the object to know which of its parts 
'X', 'Y', and 'Z' are, and what other parts it may have.

An ideal way to accomplish this would have been for you to include the
picture that accompanies the question, wherever you copied it from.


4 0
4 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
FromTheMoon [43]

\\ \sf\longmapsto \dfrac{7x}{15}-1=22

\\ \sf\longmapsto 7x/15=23

\\ \sf\longmapsto 7x=345

\\ \sf\longmapsto x=345/7

\\ \sf\longmapsto x\approx 49

8 0
2 years ago
Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL
scoray [572]

Answer:

8(x^2+y^2)-4x-30y+23=0

Step-by-step explanation:

<u />

<u>Distance formula</u>

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let P(x, y) = any point on the locus

Let A = (0, 2)    

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

PA=\dfrac{1}{3}PB

Therefore, using the distance formula:

\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}

Square both sides:

\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]

\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)

Multiply both sides by 9:

\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9

\implies 8x^2+8y^2-4x-30y+23=0

\implies 8(x^2+y^2)-4x-30y+23=0

3 0
2 years ago
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