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3 years ago

What is the equation of the line that passes through (-5, 7) and is parallel to the line y = 4x + 5?

Mathematics

1 answer:

Marysya12 [62]3 years ago

6 0

Answer:

y=4x+27

Step-by-step explanation:

If a line is parallel, it would have the same slope, so you already have that.

Now, you need the y-intercept of the second line. You already have one point, so use that point and the slope to find the y-int. What you can do (since you know you have to go up 4 and over 1, add a 1 to the -5 until you get to zero. your y-int would be 7+20 since you've gone up 5x4)

your final answer (i think) should be y=4x+27, but I could be wrong :))

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Find the equation of the circle whose center and radius are given.

vredina [299]

As i said before put the center instead of (h,k) in the general formula and put r=1
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Write the equation in standard form of a circle with center (-7,2), tangent to the y-axis.

Vesna [10]

Answer:

$(x+7)^2+(y-2)^2=7^2$

Step-by-step explanation:

Tangent to y-axis means that the side of the circle TOUCHES the y axis.

Since the center is at (-7,2) and it touches the y axis, we can figure out the radius. It goes from (-7,2) to y-axis. Horizontally, the center is 7 units left of y-axis, so that is the radius ----- 7 units

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

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(h,k) is the center

r is the radius

Putting the information into the form, we have:

$(x-h)^2+(y-k)^2=r^2\\(x-(-7))^2+(y-(2))^2=7^2\\(x+7)^2+(y-2)^2=7^2$

THis is the standard form.

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Answer:

the answer is 0.15 hope this helped u out

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