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3 years ago

12÷3×15(15-6)+3.use order of operations to solve

Mathematics

2 answers:

djverab [1.8K]3 years ago

8 0

Answer:

Step-by-step explanation:

This question its going to be pemdas.

P-parenthesis

E-exponents

M-multiply

D-divide

A-add

S-subtract

that came from left to right.

1. Calculate parenthesis.

(15-6)=9

12/3*15*9+3

2. Multiply and divide from left to right.

12/3*15*9+3

4*15*9

15*4=60

60*9

60*9=540

540+3

3. Finally, add from left to right.

=543

Final answer: 543

Hope this helps!

And thank you for posting your question at here on brainly.

Have a great day!

-Charlie

dlinn [17]3 years ago

4 0

12/3=4
4*15=60
60*(9)=540
540+3=543

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3 years ago

Which of these numbers is divisible by 8,,, 7116 4309 ,,,4136,,, 9406

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3 years ago

Read 2 more answers

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

A triangle has sides of 6 m 8 m and 11 m is it a right-angled triangle?

rewona [7]

Answer:

Step-by-step explanation:

If we use the Pythagorean theorem, we can find if it is a right triangle. To do that, set up an equation.

$6^{2}+8^{2}=c^2$

If the triangle is a right triangle, c would equal 11

Solve.

$36+64=100$

Then find the square root of 100.

The square root of 100 is 10, not 11.

So this is not a right triangle.

I hope this helps!

4 0

3 years ago