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Igoryamba
3 years ago
10

How do you factor this

Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0
Divide each side by 2a

You get 2(a^{2} - 36)
suter [353]3 years ago
3 0
(2a)(a-6)(a+6) mark as branliest tq.

Source: I'm a math teacher.
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Find the distance between the two points in simplest radical form.<br> (-9,8) and (-3, -1)
dmitriy555 [2]

Answer:

The distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

Step-by-step explanation:

Given the points

  • (-9, 8)
  • (-3, -1)

Finding the distance between (-9, 8) and (-3, -1)

d\:=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

   =\sqrt{\left(-3-\left(-9\right)\right)^2+\left(-1-8\right)^2}

   =\sqrt{\left(-3+9\right)^2+\left(-1-8\right)^2}

   =\sqrt{36+81}

   =\sqrt{117}

   =3\sqrt{13} units

Therefore, the distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

7 0
3 years ago
Find the perimeter of a square is each side is 3/4 miles long
ch4aika [34]
Three miles long.......
5 0
3 years ago
Read 2 more answers
Which statement best describes f(x)=
kotegsom [21]

Answer:

D

Step-by-step explanation:

the domain of this is x>=7

the range is x<=1

so 6 is in neither

8 0
2 years ago
Find the value of b.
Nesterboy [21]

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume \overline{AB} and \overline{BC} are tangents to the circle.

  1. \overline{BO} \cong \overline{BO} (reflexive property)
  2. \overline{AB} \cong \overline{BC} (tangents drawn from a common external point are congruent)
  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

This means the measure of minor arc AC is 130^{\circ}, and thus b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}

7 0
1 year ago
What is the solution to the equation 41/5 =15-(2x+3)
likoan [24]
\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}
4 0
3 years ago
Read 2 more answers
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