So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Step 1
<u>Find the value of s</u>
we know that
In a Rhombus all sides are congruent
so


equate AB and CD

Combine like term


<u>The answer Part a) is</u>
the value of s is 
Step 2
<u>Find the value of side AB</u>

substitute the value of s

Remember that the sides are congruent

therefore
<u>the answer Part b) is</u>
The length of the side BC is 
Answer: I got 32
Step-by-step explanation:
I got 32
I think it’s C because I did have this question but I’m not sure
Answer:
7
Step-by-step explanation:
The text of this expression is:
"If 3 is added to twice a number, the result is 17. Find the number"
Let's call
the number we want to find.
Twice the number is equal to

So, if we add 3 to 2x, we get

And we know that this is equal to 17:

Now we can solve the equation to find x: first, we subtract 3 from both sides

Now we divide both sides by 2:
