The direct answer to your question is: "No".
because in that equation, 'x' is not 120 or130.

Let's find out what 'x' actually is:

3/5 x = 52

Multiply each side by 5 : 3x = 260

Divide each side by 3 :  x = 86 and 2/3 

8 0

3 years ago

Which polynomial expression are in standard form

postnew [5]

First and third, second can still be simplified.

7 0

2 years ago

Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)

kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios between two points (x1,f(x1)) and (x2,f(x2)) is

ARC = [f(x2)-f(x1)]/ (x2-x1)

In case a)

f(-1)= -5*(-1)-8=5-8= -3 f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

In case b)

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

In case c)

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0

2 years ago

Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage. Determine the weight of a 170 cm steel bar

Bumek [7]

The weight of a 170 cm steel bar will be 5 Kg

Step-by-step explanation:

Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage.

1 kg = 1000 gm

So the weight of 1 cm steel bar will be $\frac{4 }{136}$ kg

Weight of 1 cm bar = $\frac{4000}{136}$ gm

Let the weight of a 170 cm steel bar will be $\frac{4000 }{136}$ × $170$ gm

⇒ $4000$ × $1.25$ gm

⇒ 5000 gm

⇒5 kg

Hence, the weight of a 170 cm steel bar will be 5 Kg

4 0

3 years ago