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DIA [1.3K]
3 years ago
13

A family has two cars. During one particular week, the first car consumed 15 gallons of gas and the second consumed 35 gallons o

f gas. The two cars drove a
combined total of 1700 miles, and the sum of their fuel efficiencies was 60 miles per gallon. What were the fuel efficiencies of each of the cars that week?​
Mathematics
1 answer:
bezimeni [28]3 years ago
5 0

<u>Answer: </u>

Fuel efficiencies of two cars in that week are 20 miles per gallon and 40 miles per gallon.

<u>Solution: </u>

Let the two cars of family be A and B.

Gas consumed by car A = 15 gallons

Gas consumed by car B = 35 gallons

Let’s assume number of miles car A drove in that week = x miles

Assume number of miles car B drove in that week = y miles

Given that two cars drove a combine of 1700 miles in that week.

So we can say,

x + y = 1700  --- eqn (1)

Fuel efficiency of any car = \frac{\text { Number of miles covered }}{\text { gallons of gas consumed }}

So fuel efficiency of car A = \frac{x \text { miles }}{15 \text { gallons }}

And fuel efficiency of car B = \frac{y \text { miles }}{35 \text { gallons }}

Given that sum of efficiencies of two cars = 60 miles per gallons.

\frac{x}{15}+\frac{y}{35}=60

\frac{35 x+15 y}{35 \times 15}=60

On cross-multiplication we get,

5(7x +3y) = 15 \times 35 \times 60

7x +3y = 6300  --------- eqn (2)  

Now we have following two equations and two variable to be determine.  

x + y = 1700       --------  (1)

7x +3y = 6300     --------  (2)

On modifying equation (1) we get

y = 1700 -  x        --------(3)

On substituting value of y from equation (3) in equation (2) we get

7x + 3(1700-x) = 6300

7x + 5100 – 3x = 6300

4x = 6300 – 5100  

4x = 1200

x = 300

Substituting value of x in equation 3 to get value of y

y = 1700 – 300 = 1400

Fuel efficiency of car A = \frac{x}{15} = \frac{300}{15} = 20 miles per gallon

Fuel efficiency of car B = \frac{y}{35} = \frac{1400}{35} = 40 miles per gallon.

Hence fuel efficiencies of two cars in that week are 20 miles per gallon and 40 miles per gallon.

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Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
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If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

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Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
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Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


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Answer:

Step-by-step explanation:

0: -2

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Answer:

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To work this out we need to find the highest multiple of 45 and 60.

15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.

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Therefore the odds of selecting a red candy is 3:4.

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