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elena-s [515]
3 years ago
15

When Anna was born 16 years ago, her small town of Lewisville had a population of 15,000. The population has increased 11% each

year since then. What is the current population of this town? a. The population of this town is approximately 68,925 b. The population of this town is approximately 79,663 c. The population of this town is approximately 17,324 d. The population of this town is approximately 240,000
Mathematics
2 answers:
ZanzabumX [31]3 years ago
7 0
<span>16 years ago = - 16
Present population -16 = </span><span>15,000 (population)
</span>
11% increase = every year =0.11

present year = <span>15,000 x 0.11^16 
                     = 15,000 x 4.594
approx = 68,925</span>
8_murik_8 [283]3 years ago
6 0

The correct answer is B, the population would be $79,663.

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icang [17]

Answer:

The value of gf\left(-2\right) will be:

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Step-by-step explanation:

Given the functions

f(n) = n^2 - 4n + 3

g\left(n\right)\:=\:2n\:-\:1

f\left(-2\right)\:=\:\left(-2\right)^2\:-\:4\left(-2\right)\:+\:3

           =\left(-2\right)^2+4\cdot \:2+3

           =2^2+4\cdot \:2+3

            =2^2+8+3

            =4+11

            =15

so

gf\left(-2\right)=g\left(15\right)

             =2n-1=2\left(15\right)-1=30-1=29

Therefore,

  • gf\left(-2\right)=29

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3 years ago
By selling a printer at Rs 15000 and Rs 18000, some lass and some profit are happened respectively. If the loss is one forth of
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Answer:

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