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elena-s [515]
3 years ago
15

When Anna was born 16 years ago, her small town of Lewisville had a population of 15,000. The population has increased 11% each

year since then. What is the current population of this town? a. The population of this town is approximately 68,925 b. The population of this town is approximately 79,663 c. The population of this town is approximately 17,324 d. The population of this town is approximately 240,000
Mathematics
2 answers:
ZanzabumX [31]3 years ago
7 0
<span>16 years ago = - 16
Present population -16 = </span><span>15,000 (population)
</span>
11% increase = every year =0.11

present year = <span>15,000 x 0.11^16 
                     = 15,000 x 4.594
approx = 68,925</span>
8_murik_8 [283]3 years ago
6 0

The correct answer is B, the population would be $79,663.

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The number of cases of a new disease can be modeled by the quadratic regression equation y = –2x2 + 36x + 6, where x represents
nirvana33 [79]

Since x represents the year, year 15 will be 15 years.

Plug in "15" as your "x"

y = -2(15)^2 + 36(15) + 6

15^2 = 225 (Exponents come before multiplication)

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Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

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Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

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therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

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Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

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Novosadov [1.4K]

Answer:

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Step-by-step explanation:

8 0
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