Let the planned number of parts per hour = x
<span> Then the planned number of parts for the day = 8x
</span><span> By finishing 4 more parts in an hour than was planned (x + 4) he fulfilled his daily task in 6 hours.
</span><span> So he finished 6(x + 4) parts that day.
</span><span> 6(x + 4) = 8x
</span><span> 6x + 24 = 8x
</span><span> 2x = 24
</span><span> x = 12 </span>
Yes, it should be taken into account
Answer:
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Step-by-step explanation:
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Answer:
The spread values are closer to the spread values of Manuel’s data set.
The data set is approximately symmetric.
The data set is skewed left.
Step-by-step explanation:
Its right on edmentum
