First 3 terms are a^2 + n a^(n-)1 b + n(n-1)/2 * a^(n-2) b^2
So q^2 / pr = (n^2 * a^(2n-2) * b^2 ) / (1/2 * a^n * (n(n-1) * a^(n-2) * b^2 )
= n^2 * a^2n-2 * b^2
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1/2 n(n-1) * a^(2n-2) * b^2
= 2n / n - 1 as required
given p = 4, q=32 and r = 96:-
32^2 / 4*96 = 2n / n-1
2n / n-1 = 8/3
6n = 8n - 8
2n = 8
n = 4 answer
Answer:
almost -.4
Step-by-step explanation:
The way I would answer these when I was in school, just divide -3/7.
that gives you -.428 so it is pretty close to .-4, but not exactly on it.
-4 if you have any more equations like this you can use this app called photomath
Answer:
q-22=24. Hope this helps.
Step-by-step explanation:
22 less than a number, meaning 22 is subtracted FROM an unknown variable. Going by this you would add 22 on both sides, giving you an answer of 46.
