The horizontal distance from the helicopter to the landing pad is 1658.81 feet
<em><u>Solution:</u></em>
The figure is attached below
Triangle ABC is a rightangled triangle
A helicopter is flying at point A and landing pad is at point c
Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees
The helicopter is 1250 feet from the ground
Therefore, AB = 1250 feet
To find: horizontal distance from the helicopter to the landing pad
BC is the horizontal distance from the helicopter to the landing pad
BC = ?
By the definition of tan,


Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet
The answer is 5.375
Hope that helps
The answer is B. Quadrant II
Just remember this concept instead.
we know that
the equation of a circle with the center at the origin is equal to

step 1
with the point (3,0) find the value of the radius
substitute the values of

in the equation of the circle above
so



step 2
with the radius find the area of the circle
area of the circle is equal to

for 

units²
therefore
the answer is
the area of the circle to the nearest hundredth is
units²
Y+x+3=0 will result in graph B.