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Olin [163]
2 years ago
9

On an algebra test, there are 7 students with As, 9 students with Bs, 11 students with Cs, 3 students with Ds, and 2 students wi

th Fs. Find the probability that a randomly chosen student has D. Round to the nearest tenth of a percent.
Mathematics
1 answer:
klemol [59]2 years ago
3 0
Students with D's / total students : 3 / (7 + 9 + 11 + 3 + 2) =
3 / 32 = 0.0937...to turn to a percent, multiply by 100 = 9.375....rounded =
9.4% <== ur probability
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The temperature outside is currently 10°F. It will fall at a constant rate of 3°F per hour. Which temperature will it be in 4 ho
Elenna [48]

Answer:

The temperature in 4 hours = -2 °F

Thus, option (D) is true.

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y = mx+b

where m is the rate of change or slope and b is the y-intercept

  • Let 'y' be the temperature
  • Let 'x' be the time of the temperature in the hour

Given that the current temperature outside = 10°F.

Thus, the y-intercept = b = 10°F

Given that as the day went on, It will fall at a constant rate of 3°F per hour.

Thus, the slope or rate of change = -3°F

(The rate of change or slope is -3 because the temperature is reducing)

Thus, the rate of change = slope = m = -3

Thus, substituting m = -3 and b = 10 in the equation

y = mx+b

y = -3x + 10

Now, substituting x = 4 to determine the temperature after 4 hours.

y = -3(4) + 10

y = -12 + 12

y = -2 °F

Therefore, the temperature in 4 hours = -2 °F

Thus, option (D) is true.

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3 years ago
Which point is located at (0,8)
nataly862011 [7]

The point (0, 8) simply means the x axis is 0 while the y axis is 8. The answer is C.

5 0
1 year ago
What is the volume of the following cylinder?
Vika [28.1K]
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3 0
3 years ago
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
Liula [17]

Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

7 0
3 years ago
Read 2 more answers
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