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3 years ago

Question #1:

Mathematics

1 answer:

Charra [1.4K]3 years ago

6 0

Try this solution (note, this is not the only way):

Q1: if sin(x- 3pi/2)=-sin(3pi/2- x)=--cosx=cosx, then sin(x- 3pi/2)=cosx and sin(x- 3pi/2)=7/25.

Q2: if tan(x)=√3 and x∈(180°;270°), then x=arctan√3+180°=60+180=240°.

If x=240°, then sin(x-210°)=sin30°=0.5.

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Ben also participated. He fell down midway, and had to walk part of the distance. Still, he finished the distance! It took him e

Fynjy0 [20]

Answer:

0.56 m/s

Step-by-step explanation:

The average speed of a body tells how fast is the body moving; it is calculated as:

v=\frac{d}{t}v=td

where

d is the distance covered

t is the time elapsed

In this problem, we don't know the distance covered by Ben. Therefore, we will assume that it is 1 km:

d = 1 km = 1000 m

The time elapsed to cover this distance is:

t=30 min \cdot 60 =1800 st=30min⋅60=1800s

Therefore, Ben's average speed is:

v=\frac{1000}{1800}=0.56 m/sv=18001000=0.56m/s

Hope this helps

7 0

3 years ago

How many committees of 4 boys and 3 girls can be formed from a class of 6 boys and 7 girls?

VLD [36.1K]

Answer:

525

Step-by-step explanation:

This is a question involving combinatorics

The number of ways of choosing a subset k from a set of n elements is given by ${n \choose k}$ which evaluates to $\frac{n!}{k!(n-k)!}$

n! is the product n × (n-1) × (n-2) x....x 3 x 2 x 1

For example,

4! = 4 x 3 x 2 x 1 = 24

3! = 3 x 2 x 1 = 6

Since we have to choose 4 boys from a class of 6 boys, the total number of ways this can be done is

${6 \choose 4} = \frac{6!}{4!(6-4)!} = \frac{6!}{4!2!}$

Note that 6! = 6 x 5 x 4 x 3 x 2 x 1 and 4 x 3 x 2 x 1 is nothing but 4!

So the numerator can be re-written as 6 x 5 x (4!)

We can rewrite the expression $\frac{6!}{4!2!} \text{ as } \frac{6.5.4!}{4!2!}$

Cancelling 4! from both numerator and denominator gives us the result

as (6 × 5)/2! = 20/2 = 15 different ways of choosing 4 boys from a class of 6 boys

For the girls, the number of ways of choosing 3 girls from a class of 7 girls is given by

${7 \choose 3} = \frac{7!}{3!(7-3)!} = \frac{7!}{3!4!}$

This works out to (7 x 6 x 5 )/(3 x 2 x 1) (using the same logic as for the boys computation)

= 210/6 = 35

So total number of committees of 4 boys and 3 girls that can be formed from a class of 6 boys and 7 girls = 15 x 35 = 525

8 0

2 years ago

The person who started Educational system ,was really educated?

madreJ [45]

Answer:

me plase me me please meeee

3 0

2 years ago

Read 2 more answers

Pls solve this qn..............ASAP PLS DON'T SPAMMMMM!!

Anni [7]

Probability ( a flowering plant or fruit plant) is $\frac{13}{30}$ and Probability (neem plant or peepal plant) is $\frac{29}{60}$ .

Step-by-step explanation:

Given,

Number of neem plant = 125

Number of peepal plant = 165

Number of creppers plant = 50

Number of fruit plant = 150

Number of flowering plant = 110

To find the probability ( a flowering plant or fruit plant)

and probability ( neem or peepal)

Formula

P( A or B) = P(A) + P(B)

Probability ( a flowering plant or fruit plant) = $\frac{110}{600} + \frac{150}{600}$

= $\frac{260}{600}$ = $\frac{13}{30}$

And,

Probability (neem plant or peepal plant) = $\frac{125}{600} +\frac{165}{600}$

= $\frac{290}{600}$ = $\frac{29}{60}$

4 0

3 years ago

What is the square root of 2/1

Sidana [21]

Answer:

The square root of 2/1 is

= 1.41421356237

I HOPE IT HELP YOU

6 0

2 years ago