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Amiraneli [1.4K]
4 years ago
5

These data sets provide the responses of 10 students in class A and class B who were asked how many hours they slept at night.

Mathematics
1 answer:
xenn [34]4 years ago
3 0
None of them are over 10
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Paul has three cube-shaped boxes. Each box is a different size
qwelly [4]

Answer:

See explanation

Step-by-step explanation:

Paul has three cube-shaped boxes. Each box is a different size and they are stacked from the largest to the smallest. Some information about the boxes is given below.

  • The combined volume of the three boxes is 1,197 cubic inches.
  • The area of one face of the medium box is 49 square inches.
  • The volume of the smallest box is 218 cubic inches less than the volume of the medium box.

1. The medium box has the area of one face of 49 square inches, then

a^2=49\\ \\a=7\ inches

is the side length.

The volume of the medium box is

a^3=7^3=343\ in^3.

2. The volume of the smallest box is 218 cubic inches less than the volume of the medium box, then the volume of the smallest box is

343-218=125\ in^3.

Ib is the side length, then

b^3=125\\ \\b=5\ inches

The area of one face is

b^2=5^2=25\ in^2.

3. The volume of the largest box is

1,197-343-125=729\ in^3,

then if c is the side length,

c^3=729\\ \\c=9\ inches.

4. The total height of the stack is the sum of all sides lengths:

a+b+c=7+5+9=21\ inches

5. Find the surface area of each box:

  • small 6b^2=6\cdot 5^2=6\cdot 25=150\ in^2;
  • medium 6a^2=6\cdot 7^2=6\cdot 49=294\ in^2;
  • large 6c^2=6\cdot 9^2=6\cdot 81=486\ in^2.

In total, Paul needs

150+294+486=930\ in^2

of wrapping paper. He has 1,000 square inches, so Paul has enough paper to wrap all 3 boxes.

8 0
4 years ago
Need help can someone plz help me solved this problem ASAP! Need help I will mark you as brainiest
MrRissso [65]

Answer:  2, 6

<u>Step-by-step explanation:</u>

Triangle Inequality Theorem states that the sum of two sides must be GREATER than the third side.

RS + ST > RT    and     RS + RT > ST     and     ST + RT > RS

2x + 4x > 12                  2x + 12 > 4x                  4x + 12  > 2x

       6x > 12                          12 > 2x                          12  > -2x

         x > 2                            6 > x                             -6 < x

         2 < x                             x < 6                             invalid

Answer:  2 < x < 6      

Graph:     O----------------------O

                2                          6

<em> Note: -6 is invalid because you cannot have a negative length. </em>                     

5 0
4 years ago
Help PLZ<br><br> I just need an answer it doesn't have to be correct.
Anestetic [448]

Answer:

you can decide if you want this answer or not  :D

Step-by-step explanation:

1st  , notice that our problem is about an eight part whole.  I mean,  the questions are around an object of 8 parts.  so start thinking 1/8 ths

A) asks about P(7)  ... they want to know.. how often the spinner will land on 7. so if it's totally random, 7 will happen just as likely as any of the other numbers so 7 will happen  1/8 th of the time

as a fraction  it's  1/8  as a decimal it's 0.125 and as a percent it's 12.5 %

B) asks about  P(2 or 6 )   [ btw, p here stands for probability ]  

so it's  1/8 + 1/8 =  1/4  or one quarter of the time we would get a 2 or a 6

as a fraction it's  1/4  , as a decimal it's 0.25  and as a percent it's 25%

C)   asks  about P( greater than 4)  or  P( >4)   so that's the whole left side of the circle :0  

as a fraction it's 1/2  as a decimal it's 0.5  and as a percent   it's 50%

D) P( not a 5) or P( ~=5)  so every thing but a 5

as a fraction that's 7/8  as a decimal it's 0.875 and as a percent that 87.5 %

I'll take the odds on that last one to win the lottery plz  :)  

3 0
3 years ago
Which are choices are equivalent to the quotient below ? 50/10
riadik2000 [5.3K]
5 would be equivalent to the choices.
7 0
4 years ago
Read 2 more answers
A copper smelting process is supposed to reduce the arsenic content of the copper to less than 1000 ppm. let μ denote the mean a
Hitman42 [59]
The rejection region is give by 

|z_{test}|\ \textgreater \ z_{\alpha/2}

where the test statistics is given by

\frac{\bar{x}-\mu}{\sigma/\sqrt{n}} = \frac{980-1000}{100/\sqrt{75}} \\ \\ = \frac{-20}{100/8.6603} = \frac{-20}{11.5470} =-1.73

i.e. |z_{test}|=|-1.73|=1.73

Thus, z_{\alpha/2}=1.73

Using the statistical table, the level of the test is 0.04.
6 0
4 years ago
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