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3 years ago

Louise is walking 12 miles to raise funds for a local cause. If she has completed

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

4 0

12 x 3/4 = 36/4 = 9

she has walked 9 miles

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A particular lawn mower is on sale at two different stores the original price at both stores was $130. Watson’s garden shop is a

matrenka [14]

Answer:

Watson's garden shop has the better deal on the lawn mower.

Hope this helped :)

Step-by-step explanation:

Watson's $130 - 50% = $65

Hartman's $130 - 40% = $78

$78 - 15% = About $66

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3 years ago

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Can anyone help me please??? Almost done Thank you!!

Hitman42 [59]

Answer:

you might’ve already answered this but it’s 65

Step-by-step explanation:

the two sides in a triangle have to be congruent so if one angle is 65, the other has to be 65 too :)

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HELPP!! 10 points 1 question . ( explain your answer )

Greeley [361]

50.25% off because 100÷199=50.25

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Evaluate: (4x¹⁴)(8x¹¹) *

Marta_Voda [28]

Answer:

32x^25

Step-by-step explanation:

4x^14*8x^11

6 0

3 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago