Answer:
1st problem: b) 
2nd problem: c) 
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:

where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)

Time to clean up the inside of the ( ).


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2nd Problem:
Compounded continuously problems use base as e.

P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.
Answer:
The center is (-10,10) and the radius is 4sqrt(3)
Step-by-step explanation:
(x + 10)^2 + (y - 10)^2 = 48
We can write the equation of a circle as
(x -h)^2 + (y - k)^2 = r^2 where (h,k) is the center and r is the radius
(x- -10)^2 + (y - 10)^2 = (sqrt(16*3) )^2
(x- -10)^2 + (y - 10)^2 = (4sqrt(3)) ^2
The center is (-10,10) and the radius is 4sqrt(3)
Answer:
A maximum of 306
Step-by-step explanation:
You can estimate that since each bus had less than 52 students, that 51 were on each bus. 51 times 6=306
Answer:
A.
Step-by-step explanation:
for (10,5)
5 - 5 = 2(10 - 10) = 0
for (4,-7)
-7 - 5 = 2(4 - 10) = -12
60 Are taken but the single is 1 and is that you