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4 years ago

Isosceles trapezoid ABCD has legs ABb and CD and base BC if AB =5y-3,bc=3y-3,and CD=6y-17 find the value of y

Mathematics

1 answer:

dimulka [17.4K]4 years ago

4 0

Notice the picture below

thus, solve for "y"

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Brent has a $400 console with a credit card that has 25% APR is minimum payment is $10 per month will he pay more and less than

Afina-wow [57]

Answer:

he will pay more

Step-by-step explanation:

in totoal he will pay 413.40 because apr is interest

his interest total will be 13.40$

3 0

3 years ago

If ∠WOZ and ∠WOX are supplementary angles and ∠WOX and ∠XOY are complementary angles, then what is the value of x and m∠XOY?

omeli [17]

Answer:

D.x = 6; m∠XOY = 18°

Step-by-step explanation:

Supplementary angles add to 180 and complementary angles add to 90

∠WOZ + ∠WOX = 180

108 + ∠WOX = 180

∠WOX + ∠XOY = 90

∠WOX + 3x = 90

∠WOX = 90 -3x

Replace WOX in the first equation

108 + ∠WOX = 180

108 + 90 -3x = 180

Combine like terms

198 -3x = 180

Subtract 198 from each side

-3x = 180-198

-3x = -18

Divide by -3

-3x/-3 = -18/-3

x = 6

∠XOY = 3x = 3*6 = 18

5 0

3 years ago

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

4 years ago

In circle A as shown below, segment DC is tangent to circle A at D.

Likurg_2 [28]

Answer:

AB = 3

Step-by-step explanation:

AB = AD

AB² + 4² = (AB + 2)²

AB² + 16 = AB² + 4AB + 4

combine like terms:

4AB = 12

AB = 3

4 0

3 years ago

Read 2 more answers

Please help on geometry

kondor19780726 [428]

Answer:

The Proof with Statement and Reasons is given below.

Step-by-step explanation:

Given:

∠DAF ≅ ∠EBF,

DF ≅ FE

Prove:

Δ ADF ≅ Δ BFE

Proof:

Statements Reasons

a. ∠DAF ≅ ∠EBF ...........................Given

48. ∠DFA ≅ ∠EFB  ..........................Vertical Angles are congruent

DF ≅ FE ...........................49. Given

50. Δ ADF ≅ Δ BFE  .........................By Angle-Angle-Side test

7 0

4 years ago