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sertanlavr [38]
2 years ago
11

Question and answer in the picture

Mathematics
2 answers:
SVETLANKA909090 [29]2 years ago
6 0

It's a standard form: Ax + By = C

3x-4y=12

A slop-intercept form: y = mx + b

m - slope

b - y-intercept

Convert from the standard form to the slope-intercept form:

3x-4y=12           <em>subtract 3x from both sides</em>

-4y=-3x+12        <em>divide both sides by (-4)</em>

y=\dfrac{-3}{-4}x+\dfrac{12}{-4}\\\\y=\dfrac{3}{4}x-3

Answer:

\boxed{m=\dfrac{3}{4}}

Luba_88 [7]2 years ago
3 0

Answer:

m =3/4

Step-by-step explanation:

3x-4y = 12

We need to solve for y

Subtract 3x from each side

3x-3x-4y = -3x+12

-4y = -3x+12

Divide by -4

-4y/-4 = -3x/-4 + 12/-4

y = 3/4 x -3

This is in the form y = mx+b  where m is the slope and b is the y intercept

The slope is 3/4

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JulijaS [17]

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Step-by-step explanation:

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2 years ago
Which of the following theorems verifies that ABC~WXY?
Bumek [7]

Answer:

The correct answer is option <em>B. AA</em>

<em></em>

Step-by-step explanation:

Given two triangle:

\triangle ABC  and \triangle WXY.

The dimensions given in \triangle ABC are:

\angle A = 27^\circ\\\angle B = 90^\circ

We know that the sum of three angles in a triangle is equal to 180^\circ.

\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 27+90+\angle C=180^\circ\\\Rightarrow \angle C = 63^\circ

The dimensions given in \triangle WXY are:

\angle Y = 63^\circ\\\angle X = 90^\circ

We know that the sum of three angles in a triangle is equal to 180^\circ.

\angle W+\angle X+\angle Y = 180^\circ\\\Rightarrow \angle W+90+63=180^\circ\\\Rightarrow \angle W = 27^\circ

Now, if we compare the angles of the two triangles:

\angle A = \angle W = 27^\circ\\\angle B = \angle X= 90^\circ\\\angle C = \angle Y= 63^\circ

So, by AA postulate (i.e. Angle - Angle) postulate, the two triangles are similar.

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<em>So, correct answer is option B. AA </em>

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3 years ago
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Step-by-step explanation:

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