1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVEN [57.7K]
3 years ago
5

Garbanzo bean ? garbanzo bean ?

Advanced Placement (AP)
1 answer:
zzz [600]3 years ago
3 0

Answer:

Papaya??? Oooh I know I know beannnnnnnn!!!

Explanation:

You might be interested in
Being a thief is deviant. True or False
nika2105 [10]
I would say true? ☺ Hope this helps
4 0
3 years ago
1. What career was in the “Spotlight” this month? (1 point)
kupik [55]
I don't get it theres so much symbols

6 0
3 years ago
Read 2 more answers
If the wait time is less than 30 minutes for 75% of all patients in the emergency room, what is the probability that the
Greeley [361]

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less is 0.0020

<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

  • The sample size (n) = 55 patients
  • Let's assume that the mean (x) = 32 (i.e. 58.2%) of the patients

The sample proportion \mathbf{\hat p} can be computed by using the expression:

\mathbf{\hat p = \dfrac{x}{n}}

\mathbf{\hat p = \dfrac{32}{55}}

\mathbf{\hat p =0.582}

If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}

\mathbf{( \hat P \leq 0.582 )= P \Big( Z \leq \dfrac{-0.168}{\sqrt{0.003409}} \Big )}

\mathbf{( \hat P \leq 0.582) = P \Big( Z \leq -2.88 \Big )}

From the Z distribution table:

\mathbf{( \hat P \leq 0.582) = 0.00198}

\mathbf{( \hat P \leq 0.582) \simeq 0.0020}

Learn more about probability here:

brainly.com/question/24756209

5 0
2 years ago
Read 2 more answers
In what situation must vehicles traveling on a single-lane road yield the right-of-way to other vehicles?
Sphinxa [80]

Answer:

I don't know but you blink the light when switching roads so you must blink and then change the lane hope that helps

4 0
2 years ago
Explain what indications an analysis of a postmortem forebrain can reveal about an individual’s cognitive ability.
Serhud [2]
When we compare animals to one another there<span> is a </span>correlation between<span> relative</span>brain size<span> and performance on </span>intelligence<span> tests. But we have to consider body </span>size<span>, because large animals need larger </span>brains<span> to monitor and run their large organs and higher number of nerve endings.</span>
5 0
2 years ago
Other questions:
  • What is the best way to overcome imaged risk
    10·1 answer
  • Where does wind with miller originate
    13·1 answer
  • PLEASE HELP&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;20 PTS. One degree of latitude at the equator has a standard length value
    7·1 answer
  • What is the term for the price Kelley Blue Book considers to be the correct amount one should expect to pay for a car?
    12·2 answers
  • If personal income increases,
    13·1 answer
  • What are the quilts of Gee's Bend, a community in Alabama, acclaimed for?
    9·2 answers
  • Fines are __________ when speeding violations occur within a school or construction zone.
    9·1 answer
  • A medical school is part of a
    11·1 answer
  • with regard to environmental sustainability, which of the following explains an advantage of urban light-rail networks in europe
    15·1 answer
  • BT. Phân tích cơ sở phân đoạn thị trường của sản phẩm nước xả comfort
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!