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VLD [36.1K]
3 years ago
5

plzzz help A model train is on a track 100 cm from its starting point. Turning a switch displaces the train either forward or ba

ckward 25 cm along the track depending on which way the switch is turned. Which equation models the position of the train along the track after you turn the switch? A. |x − 25| = 100 B. |x − 100| = 25 C. |x + 25| = 100 D. |x + 100| = 25
Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer: B.  |x-100| = 25

Explanation:

Draw out a number line. Mark 75, 100 and 125 on the number line as points A, B, and C in that order. Don't worry about the spacing.

The value of x represents where the train is. So if we had say x = 85, then it would be at location 85 on the number line. Writing |x-100| is the distance from x to 100. The absolute value ensures the distance is never negative. We want this distance to be 25 because after traveling 25 cm, the switch is turned, and the train goes the other way.

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Read 2 more answers
Barry wants to take out a loan from his bank for $1,000 to buy a bicycle. The interest rate on the loan from the bank is 9%. He
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Answer:

The amount that Barry would pay in interest for his loan is $15.05.

Step-by-step explanation:

To calculate this, we first calculate the monthly required fixed payment using the formula for calculating loan amortization as follows:

P = (A * (r * (1 + r)^n)) / (((1+r)^n) - 1) .................................... (1)

Where,

P = Monthly required fixed payment = ?

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Substituting all the figures into equation (1), we have:

P = ($1,000 * (0.0075 * (1 + 0.0075)^3)) / (((1 + 0.0075)^3) - 1)

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Therefore, we have:

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Therefore, the amount that Barry would pay in interest for his loan is $15.05.

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3 years ago
Kevin weighed 200 pounds when he started his diet and lost 26 pounds. What percent of his original weight did Kevin lose?
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3 years ago
The sum of three numbers is 8. The third is 9
Ierofanga [76]

Answer:

→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>

→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>

→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>

Step-by-step explanation:

• let numbers be x, y and z

{ \tt{z = 8y - 9 -  -  - (eqn \: 1)}} \\  \\ { \tt{10x = 8y - 7 -  -  - (eqn \: 2)}} \\  \\ { \tt{x + y + z = 8 -  -  - (eqn \: 3)}}

• from eqn 2, make x the subject:

{ \tt{x =  \frac{8y - 7}{10} }} \\

• substitute all variables in eqn 3:

{ \tt{ \frac{8y - 7}{10}  + y + 8y - 9 = 8}} \\  \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\  \\ { \tt{98y = 177}} \\  \\ { \boxed{ \tt{ \: y = 1.8}}}

• find z

{ \tt{z = 8y - 9}} \\  \\ { \tt{z = 8(1.8) - 9}} \\  \\ { \tt{z = 14.4 - 9}} \\  \\ { \boxed{ \tt{ \: z = 5.4 \: }}}

• find x:

{ \tt{x =  \frac{8(1.8) - 7}{10} }} \\  \\ { \tt{x =  \frac{7.4}{10} }} \\  \\ { \boxed{ \tt{ \: x = 0.74 \: }}}

Rounding to nearest value:

{ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{  \rm{z = 5}}}

7 0
3 years ago
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