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EastWind [94]
3 years ago
7

two numbers have these properties, both numbers are greater than 8. Their highest common factor is 8. their lowest common muliti

ple is 80
Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

16 and 40

Step-by-step explanation:

Hello,

We need to find the factors of 80

1, 2, 4, 5, 8, 10, 16, 20, 40 and 80.

Which can be 2, 2, 2, 2, and 5 (these numbers would go into all the factor completely without any reminder.)

This leaves us with two numbers 2 and 5

If the highest common factor (H.C.F) of both numbers is 8

And the lowest common multiple (L.C.M) = 80

Multiply the numbers by the highest common factor (H.C.F)

2 × 8 = 16

5 × 8 = 40

The numbers are 16 and 40

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one town, 64% of adults have health insurance. What is the probability that 10 adults selected at random from the town all have
Katena32 [7]

Answer:

The probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

Step-by-step explanation:

Consider the provided information.

One town, 64% of adults have health insurance.

Let p = 64% = 0.64

Therefore, q=1-0.64=0.36

We need to find the probability that 10 adults selected at random from the town all have health insurance

Use the formula: P(x)=^nC_r(p)^r(q)^{n-r}

Here, the value of r is 10.

Substitute the respective values in the above formula.

P(x)=^{10}C_{10}(0.64)^{10}(0.36)^{10-10}

P(x)=(0.64)^{10}(0.36)^{0}\\P(x)=(0.64)^{10}\\P(x)\approx0.01153

Hence, the probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

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Find all the zeroes of the polynomial function f(x)=x^3-5x^2+6x-30 using synthetic division.
WITCHER [35]
Write the coeeficientes of the polynomial in order:

  | 1   - 5   6   - 30
  |
  |
  |
------------------------

After some trials you probe with 5

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   |
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5 |        5      0       30
-----------------------------
     1     0      6        0 <---- residue

Given that the residue is 0, 5 is a root.

The quotient is x^2 + 6 = 0, which does not have a real root.

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