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EastWind [94]
3 years ago
7

two numbers have these properties, both numbers are greater than 8. Their highest common factor is 8. their lowest common muliti

ple is 80
Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

16 and 40

Step-by-step explanation:

Hello,

We need to find the factors of 80

1, 2, 4, 5, 8, 10, 16, 20, 40 and 80.

Which can be 2, 2, 2, 2, and 5 (these numbers would go into all the factor completely without any reminder.)

This leaves us with two numbers 2 and 5

If the highest common factor (H.C.F) of both numbers is 8

And the lowest common multiple (L.C.M) = 80

Multiply the numbers by the highest common factor (H.C.F)

2 × 8 = 16

5 × 8 = 40

The numbers are 16 and 40

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Answer:

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3 years ago
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What is the value of x in the equation 8x-2y=48, when y=4
Oksanka [162]
8x - 2y = 48,  y =4

8x - 2(4) = 48
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x = 56/8 = 7

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How do you make 1 1-2/1-6-7/8 a mixed number
AveGali [126]

Answer:

17/8

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2/1=2

11-2-6-7/8

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3 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

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\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

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5\sqrt{n} = 43.12

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\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

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3 years ago
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ICE Princess25 [194]

Answer:

2. 4

Step-by-step explanation:

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a-leg 1

b-leg 2 (base)

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