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3 years ago

How many solutions does this equation have? How do you know? 8x +14 - 4x = 9 + 4x - 5

Mathematics

1 answer:

MAVERICK [17]3 years ago

5 0

Answer:

no solutions.

Step-by-step explanation:

8x + 14 -4x = 9+4x -5

8x-4x -4x = 9-5-14

0x = -10

anything multiplied by 0 is 0, so it's impossible to get -10 by multiplying by 0

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A box contains marbles of five different colors: red, green, blue, yellow, and purple. there is an equal number of each color. a

olga nikolaevna [1]

P(red) = 1/5 [that says "probability of getting red is one fifth"
P(green) = 1/5
P(blue) = 1/5
P(yellow) = 1/5
P(purple) = 1/5

The reason the fractions are all the same is that there are equal numbers of each color. For example, if there were 7 marbles of each color, there would be a total of 35 marbles.

P(red) = 7/35 = 1/5
Similar for the other colors.

6 0

3 years ago

Find the measure of angle c

Vlad [161]

Answer:

Roughly 70.29 degrees

Step-by-step explanation:

Equation:

(2x+27)+(2x-11)+3x = 180

7x + 16 = 180

7x = 164

x ~ 23.43

Angle C:

3（23.43)

70.29

4 0

3 years ago

Pls help me do you know the answer let me know

FrozenT [24]

Answer:

Are you telling us to answer it all?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Need help asap or Im going to fail this class

nydimaria [60]

Answer:

The first four.

Step-by-step explanation:

There are 3 main postulates. SSS, SAS, and AAS. This simply refers to how we prove a triangle congruent. With SSS, all 3 sides must be congruent (either proven or given). AAS is when you have 2 angles congruent with a side next to one of the angles. NOT IN BETWEEN (there's an image as to what I'm talking about below). Finally, SAS. This is when you have a set of angles congruent with sides on each side congruent as well (look at the first four as an example of this.

Any more specific questions, feel free to ask!

7 0

3 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$

4 0

3 years ago