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3 years ago

Someone help Me with this please!!‼️

Mathematics

1 answer:

WINSTONCH [101]3 years ago

8 0

Answer:

Step-by-step explanation:

f(X)= 7-2x

f(3) means u have to put the value of 3 in the given equation so it will be

= 7-2×3

= 7-6

= 1

and now you have to add 6 to it so it will be 7.

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Solve for unknown: 45/15=R/9

lora16 [44]

$~~~~~~~\dfrac{45}{15} = \dfrac{R}9\\\\\\\implies \dfrac{R}9 = 3\\\\\\\implies R = 9 \times 3\\\\\\\implies R =27$

8 0

2 years ago

Review the attachments. Review the process of solving an equation and fill in the blanks.

Nezavi [6.7K]

Answer:

1) Combine like terms

2) $\sqrt[3]{x} =3$

3) cube both sides of the equation

4) $4\sqrt[3]{27} +8\sqrt[3]{27}=36$

5) 4(3) + 8(3) = 36

Step-by-step explanation:

1) Combine like terms

2) $\sqrt[3]{x} =3$

3) cube both sides of the equation

4) $4\sqrt[3]{27} +8\sqrt[3]{27}=36$

5) 4(3) + 8(3) = 36

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2 years ago

A bag contains 10 red balls, 5 blue balls and 7 green balls. Find the probability of selecting at random

Masteriza [31]

Answer:

Probably red ball because it has higher amount

4 0

2 years ago

Read 2 more answers

The product of two integers is 96. One of them is-12, find the other numbers

miss Akunina [59]

Answer:

-8

Step-by-step explanation:

let the other number be x

according to the question equation is

-12x = 96

x = 96/-12

x = -8

4 0

2 years ago

Read 2 more answers

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago