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kirill115 [55]
3 years ago
11

What is the coefficient of the following expression?

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0
The answer is -5 because a coffectient is a number that is before a variable in an algebraic expression or equation
You might be interested in
One side of a right triangle is 8 cm shorter than the hypotenuse and 7 cm shorter than the third side. Find the lengths of the s
Reptile [31]

Answer:

5 cm

Step-by-step explanation:

Let the shorter side be a, longer side be b, hypotenuse be c

By Pythagorean theorem:

a² + b² = c²

a² + (a + 7)² = (a + 8)²

a² + a² + 14a + 49 = a² + 16a + 64

a² - 2a - 15 = 0

a² + 3a - 5a - 15 = 0

a(a + 3) - 5(a + 3) = 0

(a + 3)(a - 5) = 0

a = -3 or a = 5

Because a is a side length and is a positive number

a = 5

7 0
3 years ago
Add or subtract <br> 4-2 3/7
sergeinik [125]

Answer:

subtract

Step-by-step explanation:

6 0
3 years ago
Is the product of two integers positive, negative, or zero? How can you tell?
marishachu [46]

Answer:

When you multiply a negative number by a positive number then the product is always negative. When you multiply two negative numbers or two positive numbers then the product is always positive. 3 times 4 equals 12. Since there is one positive and one negative number, the product is negative 12.

Step-by-step explanation:

3 0
3 years ago
How was ABCDEFGH transformed to A'B'C'D'E'F'G'H'?
Yanka [14]
So ur going from a smaller shape to a larger shape....means the scale factor is more then 1. The scale factor is the number that u multiply the original shape by to get the other shape.

so lets look at DE...it is 2.....and D'E' is 6

so 2 * x = 6...with ur scale factor being x
2x = 6
x = 6/2
x = 3.....so the scale factor is 3....because multiplying the original shape by 3, gives u the other shape

7 0
4 years ago
Read 2 more answers
WILL GIVE BRAINLIEST ASAPP!!!!!
Mademuasel [1]

Step-by-step explanation:

Applying rules of exponents to solve the given problems;

    4^3 x 4^5 =

    5^8 ÷ 5^-2 =

     (6^3 ) ^ 4 =

For these problems, the applicable rules of exponents are;

      aᵇ x aⁿ  = aᵇ⁺ⁿ

      aᵇ  ÷ aⁿ = aᵇ⁻ⁿ

       (aᵇ)ˣ  = aᵇˣ

For the first problem; 4³ x 4⁵

     aᵇ x aⁿ  = aᵇ⁺ⁿ

      4³ x 4⁵  = 4³⁺⁵   = 4⁸

   Second problem: aᵇ  ÷ aⁿ = aᵇ⁻ⁿ

      5⁸ ÷ 5⁻²  = 5⁸⁻⁽⁻²⁾  = 5⁸⁺²  = 5¹⁰

    Third problem;  (aᵇ)ˣ  = aᵇˣ

       (6³)⁴  = 6³ˣ⁴  = 6¹²

5 0
3 years ago
Read 2 more answers
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