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Andru [333]
3 years ago
10

20 pts and brainiest if correct

Mathematics
1 answer:
amid [387]3 years ago
7 0

We have 1 square with side length 8 inches, and 4 triangles with a base length of 8 inches and a height of 15.

Surface area = (8 × 8) + 4(0.5 × 8 × 15)

The first part of this equation is the area of the square

The second part is the area of a triangle, multiplied by 4 (because there are 4 triangles)

= 64 + 4(60)

= 64 + 240

= 304 in²

The total surface area is 304 square inches.

Let me know if you need any clarifications, thanks!

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Does 2 1/4-6/7=1 3/4
dimulka [17.4K]

Answer: No, it would be 2/5.


Step-by-step explanation: 2 1/4 - 6/7 is equal to about 1.4 when rounded to the nearest tenth. 1.4 as a fraction would be 4/10. 4/10 is simplified to 2/5 by dividing each number by 2.


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What is 5/8 + 3/4 using these sticks
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A rental hall has 60 tables.
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Plz name me brainlieset thank you

Step-by-step explanation:

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3 years ago
In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solut
Norma-Jean [14]

Differentiate the given solution:

x=C_1\cos(t)+C_2\sin(t) \implies x'=-C_1\sin(t)+C_2\cos(t)

Now, given that <em>x</em> (<em>π</em>/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have

\dfrac{\sqrt2}2=C_1\cos\left(\dfrac\pi4\right)+C_2\sin\left(\dfrac\pi4\right)

\implies\dfrac1{\sqrt2} = \dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}

\implies C_1+C_2=1

Similarly, given that <em>x'</em> (<em>p</em>/4) = 0, you have

0=-C_1\sin\left(\dfrac\pi4\right)+C_2\cos\left(\dfrac\pi4\right)

\implies 0=-\dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}

\implies C_1=C_2

From this result, it follows that

C_1+C_2=2C_1=1 \implies C_1=C_2=\dfrac12

So the particular solution to the DE that satisfies the given conditions is

\boxed{x=\dfrac12\cos(t)+\dfrac12\sin(t)}

7 0
2 years ago
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