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Reptile [31]
3 years ago
6

If X = 18 inches, Y = 80 inches, and Z = 82 inches, what is the cosine of B?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0
Cosine is probably either opp/hyp or adj/hyp
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Find the total area for the regular pyramid T.A. =
Stolb23 [73]

Answer:

The answer to your question is At = 48 + 36\sqrt{3}

Step-by-step explanation:

Area = Area of the base + Lateral area

a) Area of the base

    Area = length x height / 2

    length = 12

    height² = 12² - 6²

                 = 144 - 36

                 = 108

    height = \sqrt{108} = 6\sqrt{3}

    Area = 12 x 6\sqrt{3} / 2

              = 36\sqrt{3}

b) Lateral area

   height² = 10² - 6²

                = 100 - 36

                = 64

   height = 8

   Area = 12 x 8/2

            = 48

c) Total area

   At = 48 + 36\sqrt{3}

4 0
2 years ago
Which of the following functions is graphed below?
Pie

Answer:

C

Step-by-step explanation:

C is the solution

7 0
3 years ago
Read 2 more answers
Which expression is equivalent to the square root of 120x
iren [92.7K]
(120x)^1/2 see attached photo for steps

5 0
3 years ago
Write each phrase as a variable expression:<br><br> 9 subtracted from x
Schach [20]

Answer:

9-x

Step-by-step explanation:

7 0
3 years ago
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An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
erastova [34]

Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0
2 years ago
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