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3 years ago

How to find an area of this figure?: thanks!

Mathematics

2 answers:

mixas84 [53]3 years ago

7 0

First find the area of the triangle, then find the area of the rectangle. Finally add them together and you will get your answer.

bearhunter [10]3 years ago

3 0

The answer to that shape is 216

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H(x)=1/8x^3-x^2 Over which interval does h have a positive average rate of change?

lara31 [8.8K]

Answer:

$(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}$

Step-by-step explanation:

$h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \ respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x$

For positive rate of change $h'(x)>0$

$\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\$

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3 years ago

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fiasKO [112]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Determine the equation of the line passing through the points (4,-1) and (-2,-4)

jenyasd209 [6]

Answer:

y = 1/2x - 3

Step-by-step explanation:

the slope:

$m=\frac{-4-(-1)}{-2-4} =\frac{-4+1}{-6} =\frac{-3}{-6} =\frac{3}{6} =\frac{1}{2}$

the equation:

with the point (4, -1)

$y-(-1)=\frac{1}{2} (x-4)$

$y+1=\frac{1}{2}x-2$

$y=\frac{1}{2} x-2-1$

$y=\frac{1}{2} x-3$

I hope this help you

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Semenov [28]

Answer and work down below. Let me know if you have questions

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