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Kobotan [32]
2 years ago
13

a water tank holds 280 gallons. two percent of the water is lost at stream. how many gallons remain to be used ?

Mathematics
2 answers:
mart [117]2 years ago
3 0
If you would like to know how many gallons remain to be used, you can do this using the following steps:

lost: 2% of 280 gallons = 2% * 280 gallons = 2/100 * 280 = 5.6 gallons

280 gallons - 5.6 gallons = 274.4 gallons

The correct result would be 274.4 gallons.
Lapatulllka [165]2 years ago
3 0
2% lost.

Left = 100% - 2% = 98%

98% of 280

= 0.98*280

= 274.4

274.4 gallons remain to be used.
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Calculate the sample standard deviation of data from Question 1<br> 76,45,64,80,92
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Answer:

S.D = 15.98

Step-by-step explanation:

Given: 76,45,64,80,92

Required: Determine the standard deviation

We start by calculating the mean

Mean = \frac {\sum x}{n}

Where x-> 76,45,64,80,92 and n = 5

Mean = \frac {76+45+64+80+92}{5}

Mean = \frac{357}{5}

Mean = 71.4

Subtract Mean (71.4) from each of the given data

76 - 71.4 = 4.6\\45 - 71.4 = -26.5\\64 - 71.4 = -7.4\\80 - 71.4 = 8.6\\92 - 71.4 = 20.6

Determine the absolute value of the above result

|4.6| = 4.6\\|-26.5| = 26.5\\|-7.4| = 7.4\\|8.6| = 8.6\\|20.6| = 20.6

Square Individual Result

4.6^2 = 21.16 \\26.5^2 = 702.25\\7.4^2 = 54.76\\8.6^2 = 73.96\\20.6^2 = 424.36

Calculate the mean of the above result to give the variance

Mean = \frac {\sum x}{n}

Mean = \frac{21.16 + 702.25 + 54.76 + 73.96 + 424.36}{5}\\Mean = \frac{1276.49}{5}\\Mean = 255.298

Hence, Variance = 255.298

Standard Deviation is calculated by \sqrt{Var}

SD = \sqrt{255.298}

S.D = 15.9780474402

S.D = 15.98 (Approximated)

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