2 years ago

Evaluate \dfrac{e}{4}+2f-3 4 e +2f−3 when e=12e=12 and f=\dfrac12f= 2 1 .

Mathematics

2 answers:

Verdich [7]2 years ago

4 0

Answer: -406

Step-by-step explanation:

We have the following expression:

$\frac{e}{4}+2f-34e+2f-3$

In addition we know:

$e=12$ and $f=\frac{1}{2}$

If we substitute this in the expresion, we will have:

$\frac{12}{4}+2(\frac{1}{2})-34(12)+2(\frac{1}{2})-3=-406$

pashok25 [27]2 years ago

3 0

Answer:

it equals 1 :)

Step-by-step explanation:

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Read 2 more answers

Evaluate \dfrac{e}{4}+2f-3 4 e ​ +2f−3 when e=12e=12 and f=\dfrac12f= 2 1 ​ .

Evaluate \dfrac{e}{4}+2f-3 4 e +2f−3 when e=12e=12 and f=\dfrac12f= 2 1 .