Question

Evaluate \dfrac{e}{4}+2f-3 4 e ​ +2f−3 when e=12e=12 and f=\dfrac12f= 2 1 ​ .

Answer 1

Answer: -406

Step-by-step explanation:

We have the following expression:

$\frac{e}{4}+2f-34e+2f-3$

In addition we know:

$e=12$ and $f=\frac{1}{2}$

If we substitute this in the expresion, we will have:

$\frac{12}{4}+2(\frac{1}{2})-34(12)+2(\frac{1}{2})-3=-406$

Answer 2

Answer:

it equals 1 :)

Step-by-step explanation: