3 years ago

Evaluate \dfrac{e}{4}+2f-3 4 e +2f−3 when e=12e=12 and f=\dfrac12f= 2 1 .

Mathematics

2 answers:

Verdich [7]3 years ago

4 0

Answer: -406

Step-by-step explanation:

We have the following expression:

$\frac{e}{4}+2f-34e+2f-3$

In addition we know:

$e=12$ and $f=\frac{1}{2}$

If we substitute this in the expresion, we will have:

$\frac{12}{4}+2(\frac{1}{2})-34(12)+2(\frac{1}{2})-3=-406$

pashok25 [27]3 years ago

3 0

Answer:

it equals 1 :)

Step-by-step explanation:

You might be interested in

What is the new price of the plane ticket

Hunter-Best [27]

$250.15 aee the new price ticket

6 0

3 years ago

1/a+1/b=c solve for b how would i do this

olganol [36]

a cheap way to go about it is, let's do away with the denominators, and we'll do so by simply multiplying both sides by the the LCD of all fractions, in this case, that'd be "ab", so we multiply both sides by "ab".

$\bf \cfrac{1}{a}+\cfrac{1}{b}=c\implies\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{ab}}{ab\left( \cfrac{1}{a}+\cfrac{1}{b} \right)=ab(c)}\implies b+a=abc \\\\\\ a=abc-b\implies a=\stackrel{\textit{common factor}}{b(ac-1)}\implies \cfrac{a}{ac-1}=b$