3/20, 6/20, 9/20, 12/20 so the common difference is 3/20, ie each term is 3/20 greater than the term preceding it. Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number, in this case:
a(n)=3/20+(3/20)(n-1)
a(n)=3/20+3n/20-3/20
a(n)=3n/20 so the 5th term is:
a(4)=3*5/20=15/20=3/4
Answer:-
0
Step-by-step explanation:
h(x) = x^2 + 2x -3
x = 2
h(2) = 2^2 + 2(2) - 3
h(2) = 4 + 4 - 3
h(2) = 8-3
h(2) = 5
x = - 4
h(-4) = (-4)^2 + 2(-4) - 3
h(-4) = 16 - 8 - 3
h(-4) = 16 - 11
h(-4) = 5
========
h(2) - h(-4)
5 - 5
0
Answer:
7.
Step-by-step explanation:
7x7= 49, which is the greatest multiple before 50.
Answer:
It would be 3 because 3×4=12
(4 goes into 12 3 times)
The Answer for this is N = -4
Work shown
-5n + 31 = -14n -5
Move terms
-5n+14n=-5n-31
Collect the Like terms ThEn Calculate
9n= -36
Divide Both sides by 9
I hope This helped you
- Dante
