Commercials? idk look it up. (not on brainly lol)
Answer:
a. $80,000
Explanation:
In this question we are only concerned about the net income reported by Dodge on its income statement.
First we need to calculate ownership % in 2012 = 15% + 25% = 40%
Net income of 2012 (Gates) = $ 200000
hence Dodge will report net income of 40% of 200000 = $80000
Hence the correct answer is A
Note: Dividends will not affect the investors net income but it would reduce the investment value of Gate reported by Dodge (as it is seen as a return on investment)
Answer:
His firm's DPMO is 12,083
Explanation:
The computation of the DPMO is shown below:
= (Total complaints ÷ total number of defects opportunity) × 1 million
where,
Total complaints = Shrinkage complaints + poor quality complaints + wear off complaints + fitting issue complaints
= 22 + 16 + 12 + 8
= 58 customers defects
And, the total number of defects opportunity would be equal to
= Number of t-shirts sold × number of possible complaints
= 1,200 × 4
= 4,800
Now put these values to the above formula
So, the value would be equal to
= (58 ÷ 4,800) × 1,000,000
= 12,083
The San Francisco Giants sell tickets based on <u>dynamic pricing</u>, <span>where the prices often change based on demand and other variables.
This means that these tickets are based on how much a regular customer is willing to pay. There is an approximate price that seems reasonable for customers, and it can fluctuate, but still it is the best way to buy or sell something and profit after it. </span>
Answer:
Value of x maximising profit : x = 5
Explanation:
Cost : C(x) = x^3 - 6x^2 + 13x + 15 ; Revenue: R(x) = 28x
Profit : Revenue - Cost = R(x) - C(x)
28x - [x^3 - 6x^2 + 13x + 15] = 28x - x^3 + 6x^2 - 13x - 15
= - x^3 + 6x^2 + 15x - 15
To find value of 'x' that maximises total profit , we differentiate total profit function with respect to x & find that x value.
dTP/dx = - 3x^2 + 12x + 15 = 0 ► 3x^2 - 12x - 15 = 0
3x^2 + 3x - 15x - 15 = 0 ► 3x (x +1) - 15 (x + 1) = 0 ► (x+1) (3x-15) = 0
x + 1 = 0 ∴ x = -1 [Rejected, production quantity cant be negative] ;
3x - 15 = 0 ∴ 3x = 15 ∴ x = 15/3 = 5
Double derivate : d^2TP/dx^2 = - 6x + 12
d^2TP/dx^2 i.e - 6x + 12 at x = 5 is -6(5) + 12 = - 30+ 12 = -8 which is negative. So profit function is maximum at x = 5