Answer:
-3√5
Step-by-step explanation:
3√5-2√45
3√5-2•√9×√5
3√5-2•3√5
3√5-6√5
-3√5
Answer:
bad⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Answer:
59049 digits
Step-by-step explanation:
Given
Digits = 0 to 9
Required
Determine number of 5 digit pins that must not contain 0
There are 10 digits.
Since the pin must not contain 0, there are 9 digits left to select from.
The question didn't state that a digit can not be repeated, so I'll assume that repetition of digit is allowed.
The 1st digit of the 5 could be any of the 9 digits
The 2nd could be any of the 9 digits
The 3rd could be any of the 9 digits
The 4th could be any of the 9 digits
The 5th could be any of the 9 digits
Hence, number of selection is calculated as this:
Selection = 9 * 9 * 9 * 9 * 9
Selection = 59049
I don’t really know how to do it because i’m dumb
Answer:
the first one is 4 i think and the last one is 48 percent. im not sure if the dotted line is a underline tho
Step-by-step explanation:
:))
