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3 years ago

Can someone help please ! Answer correct for brainliest and also get a thanks ! :)

Mathematics

1 answer:

Alona [7]3 years ago

3 0

The standard deviation of the set is 5.2

To find standard deviation, we take the square root of the variance.

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What is the approximate value of the y intercept and what does it mean in this example?

nadezda [96]

Answer:

Step-by-step explanation:

By using the utility for the line of best fit,

Equation of the line of best fit will be,

y = 1.5x + 1.32

Here, y - intercept of the line = 1.32

Here, y-intercept represents the amount of bean production when the level of water applied was zero.

7 0

2 years ago

What is the simplified expression for 3a²+9ab+5-4a²-4ab+3

zheka24 [161]

Answer:

5ab + 8 - 1a^2.

Step-by-step explanation:

Combining like terms, we get 3a^2 - 4a^2 = -1a^2. We get 9ab - 4ab = 5ab. Then we get, 5 + 3 = 8. Together this is 5ab + 8 - 1a^2

5 0

3 years ago

Read 2 more answers

Find the derivative

zalisa [80]

First use the chain rule; take $y=\dfrac{x+5}{x^2+3}$ . Then

$\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dy}\cdot\dfrac{\mathrm dy}{\mathrm dx}$

By the power rule,

$f(x)=y^2\implies\dfrac{\mathrm df}{\mathrm dy}=2y=\dfrac{2(x+5)}{x^2+3}$

By the quotient rule,

$y=\dfrac{x+5}{x^2+3}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)\frac{\mathrm d(x+5)}{\mathrm dx}-(x+5)\frac{\mathrm d(x^2+3)}{\mathrm dx}}{(x^2+3)^2}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)-(x+5)(2x)}{(x^2+3)^2}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3-10x-x^2}{(x^2+3)^2}$

$\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)}{x^2+3}\cdot\dfrac{3-10x-x^2}{(x^2+3)^2}$

$\implies\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)(3-10x-x^2)}{(x^2+3)^3}$

6 0

3 years ago

Jordan wants to know how long it will take for the money she deposited to double. she has an interest rate of 4 percent. calcula

hodyreva [135]

2=1.04^t

t=ln2/(ln1.04)

t=17.673 (approx)

so t=18 (although you will have slightly more than double)

5 0

3 years ago

Read 2 more answers

A circular pond is modeled by the equipment x^2+y^2=225. A bridge over the pond is modeled by a segment of the equation x-7y=-75

makkiz [27]

X² + y² = 225
x - 7y = -75

x = 7y - 75

x² + y² = 225
(7y-75)² + y² = 225
(7y - 75)(7y - 75) + y² = 225
49y² - 525y - 525y + 5625 + y² = 225
50y² - 1050y + 5400 = 0
50(y² - 21y + 108) = 0

y² - 21y + 108 ⇒ (y - 12)(y - 9)

x = 7(12) - 75
x = 84 - 75
x = 9 ⇒ (9,12)

x = 7(9) - 75
x = 63 - 75
x = -12 ⇒ (-12,9)

3 0

3 years ago