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3 years ago

Can someone help please ! Answer correct for brainliest and also get a thanks ! :)

1 answer:

Alona [7]3 years ago

3 0

The standard deviation of the set is 5.2

To find standard deviation, we take the square root of the variance.

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Anton [14]

Answer:

88.32 L

Step-by-step explanation:

69x1.28= 88.32 L

8 0

2 years ago

inna [77]

Y = -3. Solved using elimination, although I've never seen the matrix tool before.

6 0

3 years ago

oee [108]

The answer is $0.20

When you say 3.20 ÷ 16, it gives you 0.2, but you need to add a zero at the end to make it understandable, so that is how you end up with $0.20

4 0

3 years ago

Sedbober [7]

T(x,y) -> (x-3, y+7)
is usually i have seen them parametrically defined

7 0

2 years ago

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

2 years ago