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(2x+5)(6x-1)=120
2x(6x-1)+5(6x-1)=120
12x^2-2x+30x-5=120
12x^2+28x-5-120=0
12x^2+28x-125=0
Find the roots of the equation by quadratic formula
If your trying to find the original amount all you have to do is add the 12 to the 52 to find out, that is 64!
Answer:
number 3
Step-by-step explanation:
Answer:
The point slope form of that graph would be D) y + 7 = 2/5(x + 4)
Step-by-step explanation:
We know this by plugging into the point-slope form of the equation, which is listed below.
y - y1 = m(x - x1)
y - -7 = 2/5(x - -4)
y + 7 = 2/5(x + 4)
