2 years ago

Solve the following equation -4y+8=4[2y-2]-

Mathematics

1 answer:

aksik [14]2 years ago

4 0

The answer is y=4/3. Hope this helps.

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The velocity v of blood that flows in a blood vessel with radius r and length ℓ at a distance r from the central axis is v(r) =

pogonyaev

$v(r)=4P\eta\ell(R^2-r^2)$

(assuming $R$ is the radius of the vessel, and that $0\le r\le R$ )

The average velocity of the blood is given by

$\displaystyle\frac1{R-0}\int_{r=0}^{r=R}v(r)\,\mathrm dr$
$=\displaystyle\frac{4P\eta\ell}R\int_{r=0}^{r=R}(R^2-r^2)\,\mathrm dr$
$=\dfrac{4P\eta\ell}R\left(\dfrac23R^3\right)$
$=\dfrac{8P\eta\ell}3R^2$