Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
Step-by-step explanation:
11/12-?=2/3
11/12-2/3=?
11-8/12=?
3/12
=1/4
Answer:
Step-by-step explanation:
I'm goig to assume that the formula we need here is the following:
where A(t) is the amount in the account after the compounding is done, n is the number of times per year the compounding occurs, r is the rate in decimal form, and t is the time in years. Filling in accordingly,
and simplifying a bit,
and simplifying a bit more,
A(t) = 90000(1.343916379) so
the amount in the account after 5 years is
A(t) = 120,952.47
Answer:
1254 Dont use this answer sorry
Step-by-step explanation:
