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4 years ago

What is x? 2 1/7 + 3/7(3x - 5) = -4

Mathematics

1 answer:

nasty-shy [4]4 years ago

8 0

3=x because 3x3 = 9 and when you subtract it by 5 it will be 4 or you could go add 5+4 and your answer will be 9

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Solve (6-5x)/10-(2x+1)/5+x/3=2x/15

Ulleksa [173]

Multiply2 * x/15 to 2x/15

multiply both sides by 30 which is the LCM of 10, 5, 3, and 15

expand it

simplify 18 - 15x - 12x - 6 + 10x to 12 - 17x

add 17x to both sides

add 4x + 17x to = 21x

divide both sides by 21

simplify 12/21 to 4/7

now simplify

Answer: x = 4/7.

3 0

3 years ago

Find the indicated Arc length in bold . Use 3.14 for pi!

Elenna [48]

Pretty sure it’s still 135

8 0

3 years ago

A fence is guarding off a vegetable garden in the form of a rectangle. It has one side that is 10m greater than the other side.

DanielleElmas [232]

Answer:

The length of the fence needed to surround this garden is 188 meters.

Step-by-step explanation:

Given : A fence is guarding off a vegetable garden in the form of a rectangle. It has one side that is 10 m greater than the other side.

To find : The length of the fence needed to surround this garden if the area of the vegetable garden is 2184 m² ?

Solution :

Let the one side of rectangle be 'x'.

Then the other side is 'x+10'.

The area of the rectangle is 2184 m²,

i.e. $x(x+10)=2184$

$x^2+10x-2184=0$

Solve by middle term split,

$x^2+52x-42x-2184=0$

$x(x+52)-42(x+52)=0$

$(x+52)(x-42)=0$

$x=-52,42$

Reject negative value,

The side of the rectangle is 42 m.

The other side is 42+10=52 m

The perimeter of the rectangle is $P=2(l+b)$

$P=2(42+52)$

$P=2(94)$

$P=188$

Therefore, the length of the fence needed to surround this garden is 188 meter.

5 0

3 years ago

Find the resultant matrix ~

aev [14]

$\left[\begin{array}{ccc}5\\3\\2\end{array}\right] \times[5 \ \ \ 3 \ \ \ 2]$

Matrix multiplications are defined if the number of columns in the first matrix is equal to the number of rows in the second matrix.

$\bf{\left( \begin{array}{rrr} 5 \\ 3 \\ 2 \end{array}\right) \ \ (5 \ \ 3 \ \ 2)}$

Multiply the first element of the array by the first element of the second array to get the element of the first row of the first column in the product array.

$\bf{\left( \begin{array}{rrr} 5\times5 & & \\ & & \\ & & \end{array}\right)}$

The remaining elements of the product matrix are obtained in the same way.

$\bf{ \left( \begin{array}{rrr} 5\times5 & 5\times3 & 5\times2 \\ 3\times5 & 3\times3 & 3\times2 \\ 2\times5 & 2\times3 & 2\times2 \end{array}\right) }$