1 dime is required to make $1.02 cents using 9 coins collections
<h3>How to solve</h3>
<u>Given data</u>
9 coins
a collection of pennies, nickels, dimes, and quarters
total of $1.02 with at least one coin of each type
solution
$1.02 = 102cents
1 penny = 1 cent
1 nickel = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
having one coin of each means 4 coins which is equal to:
1 + 5 + 10 + 25 = 41 cents (fulfilling the first condition remaining 5 coins)
102 - 41 = 61
balancing the remaining coins to make up 61, we first get a penny to reduce the amount 60 cents ( 4 coins remaining )
hence we have
2*25 +2*5 = 60 cents ( 2quarters 2 nickel)
in total we have
2 pennies + 3 nickels + 1 dime + 3 quarters = 9 coins
2 * 1 + 3 * 5 + 1 * 10 + 3 * 25 = 102 cents
Therefore 1 dime is required to make $1.02 cents using 9 coins collections
Read more on dimes here: brainly.com/question/435257
#SPJ1
The pattern is basically +7.
So 1 + 7 = 8; 2 + 7 = 9 and so on.
Answer:
The answer is $0.63 per pound of rice.
Step-by-step explanation:
5 ÷ 8 = 0.625
Convert 0.625 to hundredths place
0.625 = 0.63 = $0.63
Hello:
2x+3y=8
y =(-2/3)x+8/3 (the slope is : (-2/3) )
<span>an equation of the line through (-1,4) and perpendicular to 2x+3y=8</span>
<span> is : y = ax+b
the slope is a : a×(-2/3) = -1......(
perpendicular to a line with a slope of -2/3)
a = 3/2 y=(3/2)x+b
the line that passes through (-1, 4) :4 =
(3/2)(-1)+b
b =11/2
the equation is : y = (3/2)x+11/2</span>
Answer:
yikhty
Step-by-step explanation:
