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4 years ago

Another question I'm confused with.

Mathematics

1 answer:

agasfer [191]4 years ago

3 0

Hey!!

here is your answer >>>

As we have learnt, the sum of angles A and B is exterior angle ,

so,

angle B would be

( 52 + x ) = 110

x = 110 - 52

x = 58!.

angle B is 58°

Sum of all angles in a trinagle is 180!.

angle C would be ,

52 + 58 + c = 180

110 + c = 180

c = 70

angles C is 70° !.

Hope my answer helps!

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3 years ago

Scalcet8 4. 2. 26. suppose that 2 ≤ f '(x) ≤ 4 for all values of x. what are the minimum and maximum possible values of f(4) − f

ziro4ka [17]

The minimum value of f(4) - f(1) is <u>6</u>.

The maximum value of f(4) - f(1) is <u>12</u>.

In the question, we are given that, 2 ≤ f'(x) ≤ 4 for all values of x.

Taking the given inequality as (i).

We are asked to find the minimum and maximum possible values of f(4) - f(1).

We multiply (i) by dx throughout, to get:

4dx ≤ f'(x)dx ≤ 5dx.

To find this, we integrate (i) in the definite interval [4, 1] with respect to dx, to get:

$\int_{1}^{4}2dx \leq \int_{1}^{4}f'(x)dx \leq \int_{1}^{4}4dx\\\Rightarrow [2x]_{1}^{4} \leq [f(x)]_{1}^{4} \leq [4x]_{1}^{4}\\\Rightarrow 2*4 - 2*1 \leq f(4)-f(1) \leq 4*4 - 4*1\\\Rightarrow 6 \leq f(4) -f(1) \leq 12$

Thus, the minimum value of f(4) - f(1) is 6.

The maximum value of f(4) - f(1) is 12.

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2 years ago

Carl knows that the area of a given circle is 400 cm2. He wants to defend an informal argument that the area of a circle can be

Marizza181 [45]

ANSWER:

A. Carl could divide the circle into a larger even number of congruent sectors. Then each sector would be smaller, and the approximation of the circle’s area will be closer to the actual area of the circle.

STEP BY STEP EXPLANATION :

Area of a Circle by Cutting into Sectors:

1. Cut a circle into equal sectors and the more we divided the circle up, the closer we get to being exactly right.

2.Rearrange the sectors, which resembles a parallelogram.

What are the (approximate) height and width of the parallelogram?

The height is the circle's radius.

The width (actually one "bumpy" edge) is half of the curved parts around the circle. In other words it is about half the circumference of the circle.

We know that:

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And so the width is about:

Half the Circumference = π × radius

ow we just multply the width by the height to find the area of the rectangle:

Area = (π × radius) × (radius)

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Conclusion

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3 years ago

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