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stepan [7]
3 years ago
12

Please Answer I don't get it​

Mathematics
1 answer:
netineya [11]3 years ago
3 0

Answer:

What is the question?

Step-by-step explanation:

You might be interested in
-2|x-4|+7=-3 how do i solve this absolute value problem
ira [324]
Let's do this step by step:
Subtract both sides by 7
-2|x-4|= -10
Divide each side by -2
|x-4|= 5
Now since this is an absolute value equation, you will have two answers. This means you make the equation both positive and negative.
X-4= 5and -(x-4)= 5
Solve for x for both
X-4= 5: add four on both sides
X= 9
-x+ 4= 5: subtract 4 and divide by -1
X= -1
So your answer is: X= -1 , 9
4 0
3 years ago
4) HELP ASAP is about cylinders and stuff and I have to wash dishes and stuff so please help me and if you can show work that wo
Nutka1998 [239]

Answer:

<h2>C. 533.8 ft. squared</h2>

Step-by-step explanation:

Depending on the Pi that you use, the answer should be fairly close, for this I used the full Pi in the equation and got about 534.07 and answer C is closest to that answer so C is the best option.

Hope this helps! Have a good day/night!

5 0
3 years ago
Read 2 more answers
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
2 years ago
using pythagorean inequalities, determine which set of the given three sides produces an acute triangle.
Kruka [31]
To solve this problem, you need to use the Phythagorean theorem c^2 is equal to the sum of a^2 and b^2. If a less than or equal to b and b is less than or equal to c or a^2 plus  b^2  is greater than c^2 then it is an acute angle. 
5 0
2 years ago
Read 2 more answers
Which of the following describes the correct process for solving the equation 2x + 6 = 22 and arrives at the correct solution?
gulaghasi [49]

Answer:A

Step-by-step explanation:

we need to first find the answer to the equation.

2x+6=22

6-6=0

22-6=16

2x=16

divide both sides by 2

x=8

4 0
3 years ago
Read 2 more answers
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