Answer:
There are 22 quarters, 15 dimes and 72 nickels.
Step-by-step explanation:
The number of coins in the collection is 109.
Let the number of quarters = x
Let the number of dimes = y
Let the number of nickels = z
Therefore:
x + y + z = 109 -------------------------------------- (1)
There are 7 fewer dimes than quarters. This means that:
y = x - 7
=> x = y + 7
There are 3 less than five times as many nickels as dimes. This means that:
z = 5y - 3
Let us write equation (1) in terms of y to make it simpler to solve:
y + 7 + y + 5y - 3 = 109
Collecting like terms:
7y + 4 = 109
=> 7y = 105
y = 105 / 7
y = 15
Therefore:
x = 15 + 7 = 22
z = (5 * 15) - 3
z = 75 - 3 = 72
Hence, there are 22 quarters, 15 dimes and 72 nickels.
To confirm, 22 + 15 + 72 = 109
The greatest common factor of 16, 60, & 90 would be 2.
Answer:
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Solve the Function Operation
Use the given functions to set up and simplify
140
.
350
m
e
t
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r
s
=
350
m
t
e
2
r
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140
=
350
m
t
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2
r
s
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Find the Exact Value
The chosen topic is not meant for use with this type of problem. Try the examples below.
csc
(
60
)
sin
(
330
)
cos
(
390
)
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Identify the Sequence
Use the formula
a
n
=
a
1
+
d
(
n
−
1
)
to identify the arithmetic sequence.
a
n
=
700
m
t
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2
r
s
+
140
n
−
140
−
350
m
t
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2
r
s
n
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Simplify
Simplify the expression.
157.68432
m
4
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Simplify the expression.
157.68432
m
4
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Simplify the expression.
157.68432
m
4
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Solve the Function Operation
Simplify
0.9
⋅
(
0.2
m
)
⋅
(
6.9
m
)
⋅
(
13.8
m
)
⋅
(
9.2
m
)
.
157.68432
m
4
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Simplify
0.9
⋅
(
0.2
m
)
⋅
(
6.9
m
)
⋅
(
13.8
m
)
⋅
(
9.2
m
)
.
157.68432
m
4
-3^2 -3(2)^3+-3^2+2(2)^3--3^2 = -17